tính nhanh
12,48:0,5.6,25.4.2
2.3,12.1,25:0,25.10
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a) \(m_{CuSO_4}=0,3.160=48\left(g\right)\)
b) \(n_{CaCO_3}=\dfrac{9.10^{23}}{6.10^{23}}=1,5\left(mol\right)=>m_{CaCO_3}=1,5.100=150\left(g\right)\)
c) \(n_{MgCl_2}=\dfrac{1,5.10^{22}}{6.10^{23}}=0,025\left(mol\right)=>m_{MgCl_2}=0,025.95=2,375\left(g\right)\)
e) \(n_{CO_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)=>m_{CO_2}=0,1.44=4,4\left(g\right)\)
f) \(n_{NaOH}=\dfrac{0,25.10^{24}}{6.10^{23}}=\dfrac{5}{12}\left(mol\right)=>m_{NaOH}=\dfrac{5}{12}.40=16,667\left(g\right)\)
\(\dfrac{12,48:0,5.6,25.4.2}{2.3,14.1,25:0,25.10}\)
= \(\dfrac{12,48.2.5.4.2}{2.3,14.1.4.10}\)
= \(\dfrac{12,48.2}{2.3,14}\) = \(\dfrac{12,48}{3,14}\) = \(\dfrac{6,24}{1,57}\)
=<br class="Apple-interchange-newline"><div id="inner-editor"></div>12,48:0,5.6,25.4.22.3,12.1,25:0,25.10 = 12,48.2.6.25.4.22.3,12.1,25.4.10 = 3,12.4.2.1,25.5.4.22.3,12.1,25.4.5.2 = 4