(12x-5). (4x-1))+(3x-7). (1-16) bằng 81
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(12x-5).(4x-1)-(3x-7).16x=81
48x²-12x-20x+5-(48x²-112x)=81
48x²-12x-20x+5-48x²+112x=81
(48x²-48x²)+(112x-12x-20x)+5=81
0+100x-20x+5=81
80x+5=81
80x=81-5
80x=76
x=76:80
x=19/20
Vậy x=19/20
Hok tốt
\(\left(12x-5\right)\left(4x-1\right)\left(3x-7\right)\left(1-16x\right)=81\)
\(\Rightarrow\left(48x^2-12x-20x+5\right)\left(3x-7\right)\left(1-16x\right)=81\)
\(\Rightarrow\left(48x^2-32x+5\right)\left(3x-7\right)\left(1-16x\right)=81\)
\(\Rightarrow\left(144x^3-336x^2-96x^2+224x+15x-35\right)\left(1-16x\right)=81\)
\(\Rightarrow\left(144x^3-432x^2+239x-35\right)\left(1-16x\right)=81\)
\(\Rightarrow144x^3-2304x^4-432x^2+6912x^3+239x-3824x^2-35+560x=81\)
\(\Rightarrow-2304x^4+7056x^3-4256x^2+799x-116=0\)
\(\Rightarrow\left[{}\begin{matrix}x_1\approx2,3\\x_2\approx0,5\end{matrix}\right.\)
(12x - 5)(4x - 1) + (3x - 7)(1 - 16x) = 81
48x2 - 32x + 5 - 48x + 115x - 7 = 81
83x - 2 = 81
83x = 83
=> x = 1
(12x-5).(4x-1)+(3x-7).(1-16x) = 81
=> 48x2-12x-20x+5+3x-48x2-7+112x = 81
=> 83x-2 = 81
=> 83x = 81+2
=> 83x = 83
=> x = 83:83
=> x = 1
( 12x - 5 ) ( 4x -1 ) + ( 3x - 7 ) ( 1 - 16x ) = 81
48x2 - 12x - 20x + 5 + 3x - 48x2 - 7 + 112x = 81
83x = 81 - 5 + 7
83x = 83
x = 83/83
x = 1
Chúc bn hok tốt nha
\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\text{⇔}48x^2-32x+5-48x^2-7+115x=81\)
\(\text{⇔}83x-2=81\)
\(\text{⇔}83x=83\)
\(\text{⇔}x=1\)
Vậy: x=1
Ta có: \(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\)
\(\Leftrightarrow83x=83\)
hay x=1
\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\Leftrightarrow48x^2-32x+5+48x^2+115x-7=81\)
\(\Leftrightarrow83x=83\)
\(\Leftrightarrow x=1\)
\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\\ \Leftrightarrow83x=83\Leftrightarrow x=1\)
(12x - 5)(4x - 1) + (3x - 7)(1 -16x) = 81
48x2 – 12x – 20x + 5 + 3x - 48x2 – 7 + 112x = 81
83x – 2 = 81
83x = 83
x = 1