Tìm x biết 4/9.x + 0,125 = 9/8
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\(\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}\left(\dfrac{1}{8}=0,125\right)\)
\(\dfrac{4}{7}x=1\)
->x=1:\(\dfrac{4}{7}\)
-> x= \(\dfrac{7}{4}\)
Ta có: \(\dfrac{4}{7}x=\dfrac{9}{8}-0.125\)
\(\Leftrightarrow\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}=1\)
hay \(x=\dfrac{7}{4}\)
Vậy: \(x=\dfrac{7}{4}\)
*4/7x=9/8.0,125
4/7x=9/8.1/8
4/7x=9/64
x =9/64:4/7
x =9/64.7/4
x =63/256
*x-25%=1/2
x-1/4.x =1/2
x(1-1/4) =1/2
3/4.x =1/2
x =1/2:3/4
x =1/2.4/3
x =2/3
Ta có: \(\frac{7}{9}+\frac{16}{48}=\frac{10}{9}=1\frac{1}{9}\)
\(\frac{43}{8}-0,125=\frac{43}{8}-\frac{1}{8}=\frac{21}{4}=5\frac{1}{4}\)
Vì: \(1\frac{1}{9}< 2< 3< 4< 5< 5\frac{1}{4}\)
=> x= { 2;3;4;5}
a) 3/4x = 1
x = 1 : 3/4
x = 4/3
b) 4/7x = 9/8 - 0,125
4/7x = 1
x = 1 : 4/7
x = 7/4
a, \(\left(\dfrac{7}{2}-2x\right).\dfrac{10}{3}=\dfrac{22}{3}\Leftrightarrow\dfrac{7}{2}-2x=\dfrac{22}{10}=\dfrac{11}{5}\)
\(\Leftrightarrow2x=\dfrac{13}{10}\Leftrightarrow x=\dfrac{13}{20}\)
b, \(\dfrac{4x}{9}=\dfrac{9}{8}-\dfrac{125}{1000}=1\Leftrightarrow x=\dfrac{9}{4}\)
c, \(-\dfrac{x}{21}=\dfrac{60}{21}\Rightarrow x=-60\)
4/9x=9/8-0,125
4/9x=1
x=1:4/9
x=2,25