tình bằng cách hợp lí giá trị của các biểu thức sau
\(\left(-3,8\right)+\left[\left(-5,7\right)+\left(+3,8\right)\right]\)
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a)
\(\left(-3,8\right)+\left[\left(-5,7\right)+\left(+3,8\right)\right]\\ =\left(-3,8\right)+\left(-5,7\right)+3,8\\ =\left[\left(-3,8\right)+3,8\right]+\left(-5,7\right)\\ =0+\left(-5,7\right)\\ =-5,7\)
b)
\(\left(+31,4\right)+\left[\left(+6,4\right)+\left(-18\right)\right]\\ =31,4+6,4-18\\ =37,8-18\\ =19,8\)
c)
\(\left[\left(-9,6\right)+\left(+4,5\right)\right]+\left[\left(+9,6\right)+\left(-1,5\right)\right]\\ =\left(-9,6\right)+4,5+9,6-1,5\\ =\left[\left(-9,6\right)+9,6\right]+\left[4,5-1,5\right]\\ =0+3\\ =3\)
d)
\(\left[\left(-4,9\right)+\left(-37,8\right)\right]+\left[\left(+1,9\right)+\left(+2,8\right)\right]\\ =\left(-4,9\right)-37,8+1,9+2,8\\ =\left[\left(-4,9+1,9\right)\right]-\left[\left(37,8-2,8\right)\right]\\ =\left(-3\right)-35\\ =-38\)
a)(-3,8)+[(-5,7)+3,8]
=(-3,8)+(-5,7)+3,8
=(-3,8)+3,8+(-5,7)
=0+(-5,7)
=-5,7
\(A=\left(-5,85\right)+\left\{\left[\left(+41,3\right)+\left(+5\right)\right]+\left(+0,85\right)\right\}\)
\(A=\left(-5,85\right)+\left\{\left[41,3+5\right]+0,85\right\}\)
\(A=\left(-5,85\right)+\left\{41,3+5+0,85\right\}\)
\(A=\left(-5,85\right)+\left\{41,3+5,85\right\}\)
\(A=\left(-5,85\right)+41,3+5,85\)
\(A=\left(-5,85\right)+5,85+41,3\)
\(A=0+41,3\)
\(A=41,3\)
\(B=\left(-87,5\right)+\left\{\left(+87,5\right)+\left[\left(+3,8\right)+\left(-0,8\right)\right]\right\}\)
\(B=\left(-87,5\right)+87,5+3,8+\left(-0,8\right)\)
\(B=\left[\left(-87,5\right)+87,5\right]+\left[3,8+\left(-0,8\right)\right]\)
\(B=0+3\)
\(B=3\)
\(C=\dfrac{2014\left(2015^2+2016\right)-2016\left(2015^2-2014\right)}{2014\left(2013^2-2012\right)-2012\left(2013^2+2014\right)}\)
\(=\dfrac{2.2014.2016+2014.2015^2-2016.2015^2}{2014.2013^2-2012.2013^2-2.2012.2014}\)
\(=\dfrac{2.\left(2015+1\right)\left(2015-1\right)-2.2015^2}{2.2013^2-2.\left(2013+1\right)\left(2013-1\right)}\)
\(=\dfrac{2.\left(2015^2-1\right)-2.2015^2}{2.2013^2-2.\left(2013^2-1\right)}=\dfrac{-2}{2}=-1\)
\(\begin{array}{l}\left( {\frac{{20}}{7}.\frac{{ - 4}}{{ - 5}}} \right) + \left( {\frac{{20}}{7}.\frac{3}{{ - 5}}} \right) = \frac{{20}}{7}.\left( {\frac{{ - 4}}{{ - 5}} + \frac{3}{{ - 5}}} \right)\\ = \frac{{20}}{7}.\left( {\frac{{ - 1}}{{ - 5}}} \right) = \frac{{20}}{7}.\frac{1}{5} = \frac{{20}}{{35}} = \frac{4}{7}\end{array}\)
E\(=5,5.\left(-1,6\right)\)=-8,8
\(E=5,5.2-5,5.3,6\)=11-19,8=-8,8
F= -3,1.(-2,7)=8,37
F=-3,1.3+3,1.5,7=-9,3+17,67=8,37
C1:E=5,5.(2-3,6)
E=5,5.(-1,6)
E=-8,8
C2:E=5,5(2-3,6)
E=5,5.2-5,5.3,6
E=11-19,8
E=-8,8
C1:F=-3,1(3-5,7)
F=-3,1.(-2,7)
F=8,37
C2:F=-3,1(3-5,7)
F=-3,1.3-(-3,1).5,7
F=-9,3-(-17,67)
F=-9,3+17,67
F=8,37
\(\begin{array}{l}B = \left( {\frac{{ - 3}}{{13}}} \right) + \frac{{16}}{{23}} + \left( {\frac{{ - 10}}{{13}}} \right) + \frac{5}{{11}} + \frac{7}{{23}}\\ = \left[ {\left( {\frac{{ - 3}}{{13}}} \right) + \left( {\frac{{ - 10}}{{13}}} \right)} \right] + \left[ {\frac{{16}}{{23}} + \frac{7}{{23}}} \right] + \frac{5}{{11}}\\ = - 1 + 1 + \frac{5}{{11}}\\ = \frac{5}{{11}}\end{array}\)
1a, (-3,8) + [ (-5,7)+3,8]
= (-3,8+3,8) -5,7
= -5,7
b, 31,4 +[6,4 +(-18)]
= 31,4 - 11,6
= 19,8
c,[(9,6 )+4,5 ] +[9,6 +(-1,5)]
= 9,6 +9,6 +(4,5-1,5)
= 19,2 +3
=22,2
d, [ (-4,9) + (-7,8)] +[1,9+2,8]
= (-4,9 +1,9)+ (-7,8+2,8)
= -3 -5
=-8
e, (3,1-2,5)-(-2,5+3,1)
= (3,1-3,1)+(2,5-2,5)
=0
f, (5,3 -2,8 )- (4+5,3)
= (5,3-5,3) -2,8-4
= -6,8
g, -(251,3 +281 )+ 3,251 -(1-281)
= -251,3-281+3,251 -1+281
= (-281+281) -251,3 +3,251 -1
= -249,049
h,-(3/54+3/4)-(-3/4 +2/5)
= -3/54-3/4 +3/4 +2/5
=(-3/4+3/4) -3/54 +2/5
=123/270
chúc bạn học tốt
A= 2019.2018 -174.2018 -2019.2018+2019.174
A=174 (2019-2018)
A= 174
A=(2019-174)2018-2019(2018-174)
A=(2019.2018-2018.174)-(2019.2018-2018.174)
A=0
(-3,8) + [(-5,7) + ( +3,8)] = [(-3,8) + (+3,8)] + (-5,7)
= 0 + (-5,7) = -5,7