CMR : S = 1/5+1/13+1/14+1/15+1/61+1/62+1/63 < 1/2
minh thach ai lam duoc bai nay
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Ta có:
\(\frac{1}{5}=\frac{1}{5}\)
\(\frac{1}{13}+\frac{1}{14}+\frac{1}{15}<\frac{1}{12}.3=\frac{1}{4}\)
\(\frac{1}{61}+\frac{1}{62}+\frac{1}{63}<\frac{1}{60}.3=\frac{1}{20}\)
=>S<\(\frac{1}{5}+\frac{1}{4}+\frac{1}{20}=\frac{1}{2}\)
=>\(S<\frac{1}{20}\)(đpcm)
Ta có: \(S=\frac{1}{5}+\left(\frac{1}{13}+\frac{1}{14}+\frac{1}{15}\right)+\left(\frac{1}{61}+\frac{1}{62}+\frac{1}{63}\right)<\frac{1}{5}+\left(\frac{1}{13}+\frac{1}{13}+\frac{1}{13}\right)+\left(\frac{1}{61}+\frac{1}{61}+\frac{1}{61}\right)\)\(\Rightarrow S<\frac{1}{5}+\frac{3}{13}+\frac{3}{61}<\frac{1}{5}+\frac{3}{12}+\frac{3}{60}=\frac{1}{5}+\frac{1}{4}+\frac{1}{20}=\frac{1}{2}\)
\(\frac{1}{5}+\frac{1}{13}+\frac{1}{14}+\frac{1}{15}+\frac{1}{61}+\frac{1}{62}+\frac{1}{63}<\frac{1}{5}+\frac{1}{13}.3+\frac{1}{61}.3\)
\(=\frac{1}{5}+\frac{3}{13}+\frac{3}{61}<\frac{1}{5}+\frac{3}{12}+\frac{3}{60}=\frac{1}{5}+\frac{1}{4}+\frac{1}{20}=\frac{1}{2}\)
\(\Rightarrowđpcm\)
Ta có:
S=1/5+(1/13+1/14+1/15)+(1/61+1/62+1/63)<1/5+1/12.3+1/60.3
=>S<1/5+1/4+1/20=10/20
Hay S<1/2
\(S=\frac{1}{5}+\left(\frac{1}{13}+\frac{1}{14}+\frac{1}{15}\right)+\left(\frac{1}{61}+\frac{1}{62}+\frac{1}{63}\right)\)
\(\Rightarrow S< \frac{1}{5}+\frac{1}{12}.3+\frac{1}{60}.3\)
\(\Rightarrow S< \frac{1}{5}+\frac{1}{4}+\frac{1}{20}\)
\(\Rightarrow S< \frac{1}{2}\)