Tính bằng cách hợp lí:4/15*3/8+4/15*5/8=
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\(a,\dfrac{3}{2}\times\dfrac{4}{5}\times\dfrac{2}{3}\times\dfrac{15}{4}\\ =\dfrac{3\times4\times2\times15}{2\times5\times3\times4}\\ =\dfrac{3\times4\times2\times5\times3}{2\times5\times3\times4}\\ =3\)
\(b,\dfrac{6}{7}\times\dfrac{5}{8}\times\dfrac{7}{3}\times\dfrac{7}{6}\times\dfrac{8}{5}\\ =\dfrac{6\times5\times7\times7\times8}{7\times8\times3\times6\times5}\\ =\dfrac{7}{3}\)
a) \(\dfrac{3}{2}\times\dfrac{4}{5}\times\dfrac{2}{3}\times\dfrac{15}{4}\)
\(=\left(\dfrac{3}{2}\times\dfrac{2}{3}\right)\times\left(\dfrac{4}{5}\times\dfrac{15}{4}\right)\)
\(=1\times3\)
\(=3\)
b) \(\dfrac{6}{7}\times\dfrac{5}{8}\times\dfrac{7}{3}\times\dfrac{7}{6}\times\dfrac{8}{5}\)
\(=\left(\dfrac{6}{7}\times\dfrac{7}{6}\right)\times\left(\dfrac{5}{8}\times\dfrac{8}{5}\right)\times\dfrac{7}{3}\)
\(=1\times1\times\dfrac{7}{3}\)
\(=\dfrac{7}{3}\)
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\(a,1\dfrac{4}{7}.3\dfrac{4}{11}.3\dfrac{11}{15}.5\dfrac{5}{8}\)
\(=\dfrac{11}{7}.\dfrac{27}{11}.\dfrac{56}{15}.\dfrac{45}{8}\)
\(=\dfrac{11.27.56.45}{7.11.15.8}\)
\(=\dfrac{1.3.7.3}{1.1.1.1}\)
\(=63\)
\(b,\dfrac{3}{4}.1\dfrac{1}{2}+\dfrac{3}{4}.\dfrac{1}{2}\)
\(=\dfrac{3}{4}.\left(1\dfrac{1}{2}+\dfrac{1}{2}\right)\)
\(=\dfrac{3}{4}.2\)
\(=\dfrac{3}{2}\)
\(=\left(-\dfrac{5}{9}-\dfrac{4}{9}\right)+\left(\dfrac{8}{15}+\dfrac{7}{15}\right)-\dfrac{2}{11}=-\dfrac{2}{11}\)
\(\dfrac{-5}{9}+\dfrac{8}{15}+\dfrac{-2}{11}+\dfrac{4}{-9}+\dfrac{7}{15}.\\ =\left(\dfrac{-5}{9}+\dfrac{-4}{9}\right)+\left(\dfrac{8}{15}+\dfrac{7}{15}\right)-\dfrac{2}{11}.\\ =-1+1-\dfrac{2}{11}.\\ =-\dfrac{2}{11}.\)
a) \(-\frac{4}{15}\cdot\left(-\frac{3}{8}\right)\cdot\left(\frac{15}{-4}\right)\cdot8\)
\(=\left(-\frac{4}{15}\cdot\left(\frac{15}{-4}\right)\right)\cdot\left(-\frac{3}{8}\cdot8\right)\)
\(=1\cdot\left(-3\right)=-3\)
b) \(-\frac{2}{3}\cdot\frac{4}{19}+\frac{5}{3}\cdot\frac{4}{19}\)
\(=\frac{4}{19}\cdot\left(\frac{5}{3}-\frac{2}{3}\right)\)
\(=\frac{4}{19}\cdot1=\frac{4}{19}\)
c) \(-\frac{1}{2}\cdot\frac{5 }{3}+\frac{1}{2}\cdot\frac{8}{3}\)
\(=\frac{1}{2}\left(\frac{8}{3}-\frac{5}{3}\right)\)
\(=\frac{1}{2}\cdot1=\frac{1}{2}\)
\(\begin{array}{l}1,2.\frac{{15}}{4} + \frac{{16}}{7}.\frac{{ - 85}}{8} - 1,2.5\frac{3}{4} - \frac{{16}}{7}.\frac{{ - 71}}{8}\\ =(1,2.\frac{{15}}{4} - 1,2.5\frac{3}{4}) +( \frac{{16}}{7}.\frac{{ - 85}}{8}- \frac{{16}}{7}.\frac{{ - 71}}{8}) \\= \frac{{12}}{{10}}.\frac{{15}}{4} - \frac{{12}}{{10}}.\frac{{23}}{4} + \frac{{16}}{7}.\frac{{ - 85}}{8} - \frac{{16}}{7}.\frac{{ - 71}}{8}\\ = \frac{6}{5}.\frac{{15}}{4} - \frac{6}{5}.\frac{{23}}{4} + \frac{{16}}{7}.\frac{{ - 85}}{8} + \frac{{16}}{7}.\frac{{71}}{8}\\ = \frac{6}{5}.(\frac{{15}}{4} - \frac{{23}}{4}) + \frac{{16}}{7}.(\frac{{ - 85}}{8} + \frac{{71}}{8})\\ = \frac{6}{5}.\frac{{ - 8}}{4} + \frac{{16}}{7}.\frac{{ - 14}}{8}\\ = \frac{6}{5}.( - 2) + ( - 4)\\ = \frac{{ - 12}}{5} + \frac{{ - 20}}{5}\\ = \frac{{ - 32}}{5}\end{array}\)
Chú ý: Nếu phân số chưa tối giản, ta nên tối giản phân số trước để việc tính toán được thuận tiện hơn.
B = 1.3/2.2 . 2.4/3.3 . 3.5/4.4 . ...... . 9.11/10.10
= 1.2.3 . ..... . 9/2.3.4 . ..... . 10 . 3.4.5 . ...... . 11/2.3.4 . ..... . 10
= 1/10 . 11/2
= 11/20
Tk mk nha
\(B=\frac{3}{4}.\frac{8}{9}...\frac{99}{100}\)
\(B=\frac{1\cdot3}{2^2}.\frac{2\cdot4}{3^3}...\frac{9\cdot11}{10^2}\)
\(B=\frac{1.3.2.4...9.11}{2^2.3^3...10^2}\)
\(B=\frac{11}{2.10}\)
\(B=\frac{11}{20}\)
\(\dfrac{5}{13}.\dfrac{8}{15}+\dfrac{5}{13}.\dfrac{26}{15}-\dfrac{5}{13}.\dfrac{8}{15}.\\ =\dfrac{5}{13}.\left(\dfrac{8}{15}+\dfrac{26}{15}-\dfrac{8}{15}\right).\\ =\dfrac{5}{13}.\dfrac{26}{15}=\dfrac{2}{3}.\)
4/15 x 3/8 + 4/15 x 5/8
= 4/15 x (3/8 + 5/8)
= 4/15 x 1
= 4/15
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