Tìm x € N : biết
A) ( 3 x -6 ) .3 = 34
B) 2 x .4 = 128
C) ( 2 x + 1) mũ 3 = 125
Giúp mk giải bài này nha
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a) 128 - 3(x + 4) = 23
3(x + 4) = 128 -23
3(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
\(a.128-3\left(x+4\right)=23.\)
\(3\left(x+4\right)=128-23\)
\(3\left(x+4\right)=105\)
\(x+4=105:3=35\)
\(x=35-4=31\)
\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)
\(\left(4x+28\right)\cdot3=175-55=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
1. 15^x=225
<=>15^x=15^2
=>x=2
vậy....
2. x^3=27
<=>x^3=3^3
=>x=3
vậy......
3. 4.2^x-3=125
4.2^x=128
2^x=32
2^x=2^5
=>x=5
vậy.....
\(15^x=225\)
\(\Leftrightarrow15^x=15^2\)
\(\Leftrightarrow x=2\)
\(x^3=27\)
\(\Leftrightarrow x^3=3^3\)
\(\Leftrightarrow x=3\)
\(4.2^x-3=125\)
\(\Leftrightarrow4.2^x=125+3\)
\(\Leftrightarrow4.2^x=128\)
\(\Leftrightarrow2^x=128:4\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
~ Hok tốt ~
a)2^x-15=17
2^x=17+15=32
2^x=32=>x=5(vì 2^5=32)
b)mk ko bt cách giải
c)7^2-(15+x)=5.2^2
49-(15+x)=5.4=20
15+x=49-20
15+x=29
d)mk cx ko bt cách giải nhưng mk bt x=2(bn thử lại là bt)
b) (7x-11)3= 25.52+200
(7x-11)3 = 25.52 + 23.52
(7x-11)3 = 23.52( 22+1)
(7x-11)3 = 8 . 25 . 5
(7x-11)3 = 1000
(7x-11)3 = 103
=> 7x-11 = 10
7x = 10+11
7x = 21
x= 3
d) (2x+1)3 = 125
(2x+1)3 = 53
=> 2x + 1 = 5
=> 2x = 5-1
2x = 4
x=2
a) 2x : 4 = 128
=> 2x = 512
=> 2x = 29
=> x = 9
b) x15 = x
=> x15 = x15
=> x = 1 hoặc 0
c) ( 2x + 1 )3 = 125
=> ( 2x + 1 )3 = 53
=> 2x + 1 = 5
=> 2x = 4
=> x = 2
a) 2x : 4 = 128
=> 2x = 128 . 4
=> 2x = 512
=> 2x = 29
=> x = 9
b) x15 = x
=> x15 = x15
=> x = 1 hoặc 0
c) ( 2x + 1 )3 = 125
=> ( 2x + 1 )3 = 53
=> 2x + 1 = 5
=> 2x = 5 - 1
=> 2x = 4
=> x = 4 : 2
=> x = 2
Bài 6 :
a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)
b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)
c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)
d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)
Bài 7 :
a) \(3^x+3^{x+2}=9^{17}+27^{12}\)
\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)
\(\Rightarrow10.3^x=3^{34}+3^{36}\)
\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)
\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)
b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)
\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)
\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)
c) Bài C bạn xem lại đề
d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)
\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)
\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)
\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)
\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)
\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)
b)\(3.4^2-2.3=3.\left(4^2-3\right)\)
\(=3.13\)
\(=39\)
Học tốt nha!!!
3:
a: 3^x*3=243
=>3^x=81
=>x=4
b; 2^x*16^2=1024
=>2^x=4
=>x=2
c: 64*4^x=16^8
=>4^x=4^16/4^3=4^13
=>x=13
d: 2^x=16
=>2^x=2^4
=>x=4