36 | \times× | 36 | = | \times× | = | = | ||||
16 | 21 | 4 | 7 | 28 | 7 |
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\(18+\dfrac{1}{11}\times\left(x-18\right)=36+\dfrac{1}{11}\times\left[\dfrac{10}{11}\times\left(x-18\right)-36\right]\)
\(\Leftrightarrow\dfrac{198}{11}+\dfrac{1}{11}\times\left(x-18\right)=36+\dfrac{1}{11}\times\left[\dfrac{10}{11}\times\left(x-18\right)-\dfrac{396}{11}\right]\)
\(\Leftrightarrow\dfrac{198+x-18}{11}=36+\dfrac{1}{11}\times\dfrac{10x-180-396}{11}\)
\(\Leftrightarrow\dfrac{180+x}{11}=36+\dfrac{10x-576}{121}\)
\(\Leftrightarrow\dfrac{1980+11x}{121}=\dfrac{4356}{121}+\dfrac{10x-576}{121}\)
\(\Leftrightarrow1980+11x=4356+10x-576\)
\(\Leftrightarrow11x-10x=4356-1980-576\)
\(\Leftrightarrow x=1800\)
a: A=120-61x(-8)
=120+488=608
b: =47(-136+36)-(-1)
=-4700+1=-4699
c: C=(-48-304+72)+36
=-352+72+36
=-280+36=-244
17,5 x 63 + 17,5 x 36 + 10 + 7,5
= 17,5 x 63 + 17,5 x 36 + 17,5 x 1
= 17,5 x (63 + 36 + 1)
= 17,5 x 100
= 1750
= 17,5 x 63 + 17,5 x 36 + 17,5 x 1
= 17,5 x (63 + 36 + 1)
= 17,5 x 100
= 1750
a) \(A=125\left(-24\right)+24.225\)
\(=24\left[\left(-125\right)+225\right]\)
\(=24.100=2400\)
b) \(B=26\left(-125\right)-125\left(-36\right)\)
\(=125\left[\left(-26\right)-\left(-36\right)\right]\)
\(=125.10=1250\)
c) \(C=25\left(75-45\right)-75\left(45-25\right)\)
\(=25.75-25.45-75.45-75.25\)
\(=\left(25.75-75.25\right)-25.45-75.45\)
\(=-25.45-75.45\)
\(=45\left(-25-75\right)\)
\(=45\left(-100\right)=-4500\)
\(A=\frac{20}{21}\cdot\frac{27}{28}\cdot\frac{35}{36}\cdot...\cdot\frac{1325}{1326}\)
\(=\frac{40}{42}\cdot\frac{54}{56}\cdot\frac{70}{72}\cdot...\cdot\frac{2650}{2652}\)
\(=\frac{5\cdot8}{6\cdot7}\cdot\frac{6\cdot9}{7\cdot8}\cdot\frac{7\cdot10}{8\cdot9}\cdot...\cdot\frac{50\cdot53}{51\cdot52}\)
\(=\frac{5\cdot53}{7\cdot51}=\frac{265}{357}\)
a: th1: a>0
=>-17a<27a
th2: a=0
=>-17a=27a
th3: a<0
=>-17a>27a
b:
TH1: a>6
36>31
nên 36(a-6)>31(a-6)
TH2: a<6
36>31
nên 36(a-6)<31(a-6)
9/4 x 12/7= 108/28 = 27/7
36/16 x 36/21 = 9/4 x 12/7 = 108/28 = 27/7