(1/4 x X -1/8) x 3/4 = 1/4
bài tìm x
x nhỏ là nhân
X lớn là x trong bài tìm x
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Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)
Bài 2:
a: \(\Leftrightarrow x-1\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
=>\(x\in\left\{2;0;3;-1;4;-2;7;-5\right\}\)
b: \(\Leftrightarrow x+3\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
=>\(x\in\left\{-2;-4;0;-6;2;-8;12;-18\right\}\)
c: \(\Leftrightarrow x+3\in\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)
=>\(x\in\left\{-2;-4;-1;-5;0;-6;1;-7;3;-9;9;-15\right\}\)
d: =>x+1+15 chia hết cho x+1
=>\(x+1\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
=>\(x\in\left\{0;-2;2;-4;4;-6;14;-16\right\}\)
Bài 1;
\(\frac{5}{7}=\frac{10}{14}\); \(\frac{6}{7}=\frac{12}{14}\)
=> \(\frac{10}{14}< \frac{11}{14}< \frac{12}{14}=>\frac{5}{7}< \frac{11}{14}< \frac{6}{7}\)
\(\left(\frac{1}{4}xX-\frac{1}{8}\right)x\frac{3}{4}=\frac{1}{4}\)
\(\left(\frac{1}{4}xX-\frac{1}{8}\right)=\frac{1}{4}:\frac{3}{4}\)
\(\left(\frac{1}{4}xX-\frac{1}{8}\right)=\frac{1}{3}\)
\(\frac{1}{4}xX=\frac{1}{3}+\frac{1}{8}\)
\(\frac{1}{4}xX=\frac{11}{24}\)
\(x=\frac{11}{24}:\frac{1}{4}\)
\(x=\frac{11}{6}\)
1/4 . x -1/8 = 3/4 : 1/4
1/4 . x -1/8 = 3
1/4 . x =3+1/8
1/4 . x = 25/8
x = 25/8 : 1/4
x = 25/2
Lớp 7 rồi nên mk viết dấu nhân là ( . )nhé