tính bằng cách thuận tiện nhất: 7/8 + 4/23 + 42/23 bằng bao nhiêu?
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(53+47)+(23+77)+(42+58)+(93+7)+(91+9)
100+100+100+100+100
500
học tốt
21+22+23+24+25+26+9+8+7+6+5+4 =180
mình thấy rồng con lon ton làm đúng đấy
\(\frac{19}{15}+\frac{31}{23}-\frac{4}{15}-\frac{8}{23}=\frac{19-4}{15}+\frac{31-8}{23}=\frac{15}{15}+\frac{23}{23}=1+1=2\)
\(\frac{19}{15}+\frac{31}{23}-\frac{4}{15}-\frac{8}{23}\)
\(=\frac{19-4}{15}+\frac{31-8}{23}\)
\(=\frac{15}{15}+\frac{23}{23}\)
\(=1+1=2\)
a) \(\frac{7}{18}+\frac{4}{23}+\frac{11}{18}+\frac{19}{23}\)
\(=\left(\frac{7}{18}+\frac{11}{18}\right)+\left(\frac{4}{23}+\frac{19}{23}\right)\)
\(=1+1\)
\(=2\)
b) \(\frac{19}{15}+\frac{31}{23}-\frac{4}{15}-\frac{8}{23}\)
\(=\left(\frac{19}{15}-\frac{4}{15}\right)+\left(\frac{31}{23}-\frac{8}{23}\right)\)
\(=1+1\)
\(=2\)
ủng hộ tớ nha
\(5\dfrac{3}{4}:3+2\dfrac{1}{4}\times\dfrac{1}{3}-\dfrac{1}{8}=\left(5\dfrac{3}{4}+2\dfrac{1}{4}\right)\times\dfrac{1}{3}-\dfrac{1}{8}\\ =8\times\dfrac{1}{3}-\dfrac{1}{8}=\dfrac{8}{3}-\dfrac{1}{8}=\dfrac{61}{24}\\ ----\\ \dfrac{3}{5}:\dfrac{5}{6}:\dfrac{6}{7}:\dfrac{7}{8}+\dfrac{2}{5}+\dfrac{23}{35}\\ =\dfrac{3}{5}\times\dfrac{6}{5}\times\dfrac{7}{6}\times\dfrac{8}{7}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{18}{25}\times\dfrac{4}{3}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{353}{175}\)
a) = \(\left(\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{1}{7}\right):\dfrac{27}{31}\)
= \(\dfrac{7}{7}\) x \(\dfrac{31}{27}\)
= 1 x \(\dfrac{31}{27}\) = \(\dfrac{31}{27}\)
b) = \(\left(\dfrac{23}{45}:\dfrac{23}{45}\right)\)x \(\dfrac{17}{51}\)
= 1 x \(\dfrac{17}{51}\)= \(\dfrac{17}{51}\)
\(\frac{19}{15}+\frac{31}{23}-\frac{4}{15}-\frac{8}{23}\)
\(=\left(\frac{19}{15}-\frac{4}{15}\right)+\left(\frac{31}{23}-\frac{8}{23}\right)\)
\(=\frac{15}{15}+\frac{23}{23}\)
\(=1+1=2\)
\(\frac{19}{15}+\frac{31}{23}-\frac{14}{15}-\frac{8}{23}\)
\(=\frac{19}{15}-\frac{4}{15}+\frac{31}{23}-\frac{8}{23}\)
\(=1+1=2\)
chúc bạn học giỏi
TL
\(\frac{7}{8}\)+\(\frac{4}{23}\)+\(\frac{42}{23}\)=\(\frac{7}{8}+2\)=\(\frac{23}{8}\)
nha bn
HT
\(TL:\)
\(\frac{7}{8}+\frac{4}{23}+\frac{42}{23}\)
\(=\frac{7}{8}+\left(\frac{4}{23}+\frac{42}{23}\right)\)
\(=\frac{7}{8}+\frac{46}{23}\)
\(=\frac{7}{8}+2\)
\(=\frac{7}{8}+\frac{16}{8}\)
\(=\frac{23}{8}\)
\(=2\frac{7}{8}\)
\(HT!\)