tính nhanh\(\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)x\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right)\)
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\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\text{ }\)
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).0\)
\(Q=0\)
Q=(1/99+12/999+123/999).(1/2-1/3-1/6) =(1/99+12/999+123/999).0 Q=0
\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).0\)
\(=0\)
\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)=\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right).0=0\)
Ta có: B= (1/99+12/999-123/9999).(1/2-1/3-1/6)
B= (1/99+12/999-123/9999).(3/6-2/6-1/6)
B= (1/99+12/999-123/9999).0
B= 0
B = (1/99+12/999-123/9999).(1/2-1/3-1/6)
B= (1/99+12/999+123/9999).0
B=0
tk mình nha !
A=(9/1999+99/999+999/9999).(1/5-1/4+1/20)
A=(9/1999+99/999+999/9999).(-1/20+1/20)
A=(9/1999+99/999+999/9999).0
A=0
Vì mọi số nhân vs 0 thì đều = 0 kể cả phân số
mk nhanh nhất ủng hộ nha
\(A=\left(\frac{9}{1999}+\frac{99}{999}+\frac{999}{9999}\right)\cdot0\)
A=0
\(\left(\frac{99^9}{11^9}-\frac{99^{99}}{11^{99}}-\frac{99^{999}}{11^{999}}\right)\left(\frac{1}{5}-\frac{1}{7}-\frac{2}{35}\right)\)
\(=\left(\frac{99^9}{11^9}-\frac{99^{99}}{11^{99}}-\frac{99^{999}}{11^{999}}\right)\left(\frac{7}{35}-\frac{5}{35}-\frac{2}{35}\right)\)
\(=\left(\frac{99^9}{11^9}-\frac{99^{99}}{11^{99}}-\frac{99^{999}}{11^{999}}\right).0\)
\(=0\)
=0x(1/99+12/999+123/99990
=0