Question

[Vũ Trần Hưng]

Cho G=5/3+8/3^2+11/3^3+...+302/3^100.Chứng minh 2 5/9<G<3 1phần 2

Answer 1

[tribinh]

3G = 3(5/3+8/3^2+11/3^3+...+302/3^100) = 5 + 8/3 + 11/3^2 + ... + 302/3^99

3G - G = ( 5 + 8/3 + 11/3^2 + ... + 302/3^99 ) - ( 5/3+8/3^2+11/3^3+...+302/3^100 ) 

2G = 5 + 8/3 + 11/3^2 + ... + 302/3^99 - 5/3 - 8/3^2 - 11/3^3 - ... - 302/3^100

2G = 5 + 1 + 1/3 + 1/3^2 + ... + 1/3^98 - 302/3^100                  (1)

Đặt B = 1/3 + 1/3^2 + 1/3^3 + ... + 1/3^98

3B = 1 + 1/3 + 1/3^2 + ... + 1/3^97

3B - B = 1 + 1/3 + 1/3^2 + ... + 1/3^97 - 1/3 - 1/3^2 - 1/3^3 - ... - 1/3^98

2B = 1 - 1/3^98

B = 1/2 - 1/3^98         (2)

Từ (1) và (2) => 2G = 5 + 1 + 1/3 + 1/3^2 + ... + 1/3^98 - 302/3^100 = 6 + 1/2 - 1/3^98

=> G = 3 + 1/4 - 1/3^98

ta có 0 < 1/4 - 1/3^98 < 1/2

=> 3 < 3 + 1/4 - 1/3^98 < 3 + 1/2      

suy ra 2 + 5/9 < G < 3 + 1/2

Answer 2

[nguyễn nhật khải bình]

bạn có: 3G = (5 + 8/3) + (11/3^2 + 14/3^3 + ... + 299/3^98 + 302/3^99)
              G = 5/3 + (8/3^2 + 11/3^3 + .... + 296/3^98 + 299/3^99 + 302/3^100)
bạn có 3G - G = 5 + 8/3 - 5/3 + (11/3^2 - 8/3^2) + (14/3^3 - 11/3^3) + .... + (299/3^98 - 296/3^98) + (302/3^99 - 299/3^99) - 302/3^100
hay 2G = 5 +8/3 - 5/3 + (3/3^2 + 3/3^3 + ... + 3/3^98 + 3/3^99) - 302/3^100 
       2G = 6 + (1/3 + 1/3^2 +... + 1/3^97 + 1/3^98)

đặt H = 1/3 + 1/3^2 + ... + 1/3^97 + 1/3^98
 suy ra ta có 3H = 1 + 1/3 + .... + 1/3^96 + 1/3^97
3H - H = 1 - 1/3^98 hay 2H = 1 - 1/3^98

ở trên bạn có:
2G = 6 + (1/3 + 1/3^2 +... + 1/3^97 + 1/3^98)
hay 2G = 6 + H
hay 4G = 12 + 2H
hay 4G = 12 + 1 - 1/3^98
hay G = 13/4 - (1/3^98)/4