rút gọn rồi tính
4/5+3/15
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Rút gọn rồi tính: \(a.\frac{16}{24}-\frac{1}{3}=\frac{2}{3}-\frac{1}{3}=\frac{1}{3}\)
\(b.\frac{4}{5}-\frac{12}{60}=\frac{4}{5}-\frac{1}{5}=\frac{3}{5}\)
Tính rồi rút gọn:
\(a.\frac{17}{6}-\frac{2}{6}=\frac{15}{6}\)
\(b.\frac{16}{15}-\frac{11}{15}=\frac{5}{15}=\frac{1}{3}\)
\(c.\frac{19}{12}-\frac{13}{12}=\frac{6}{12}=\frac{1}{2}\)
1a2/3-1/3=1/3 c4/5-1/5=3/5 tinh roi rut gon 17/6-2/6=15/6=5/2 16/15-11/15=5/15=1/3 19/12-13/12=6/12=1/2
chuc bn hoc tot
1, Rút gọn rồi tính
a) \(\frac{4}{5}+\frac{3}{15}\)
= \(\frac{4}{5}+\frac{1}{5}\)
= \(\frac{5}{5}\)
= \(1\)
b) \(\frac{2}{3}+\frac{32}{24}\)
= \(\frac{2}{3}+\frac{4}{3}\)
= \(\frac{6}{3}\)
= \(2\)
c) \(\frac{5}{6}+\frac{15}{18}\)
= \(\frac{5}{6}+\frac{5}{6}\)
= \(\frac{10}{6}\)
= \(\frac{5}{3}\)
2, Tính rồi rút gọn
a) \(\frac{8}{15}+\frac{2}{3}\)
= \(\frac{8}{15}+\frac{10}{15}\)
= \(\frac{18}{15}\)
= \(\frac{6}{5}\)
b) \(\frac{3}{7}+\frac{4}{8}\)
= \(\frac{24}{56}+\frac{28}{56}\)
= \(\frac{52}{56}\)
= \(\frac{13}{14}\)
( 2/5 +3/4 ) * 2/3 - 8/15 = 23/20 * 2/3 -8/15
= 23/30 - 8/15 = 7/30
a) \(...=\dfrac{5}{6}-\dfrac{4}{15}=\dfrac{75}{90}-\dfrac{24}{90}=\dfrac{51}{90}\)
b) \(...=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{5}{10}-\dfrac{2}{10}=\dfrac{3}{10}\)
\(\dfrac{25}{30}\) - \(\dfrac{4}{15}\) = \(\dfrac{5}{6}\) - \(\dfrac{4}{15}\) = \(\dfrac{17}{30}\)
\(\dfrac{27}{54}\) - \(\dfrac{3}{15}\) = \(\dfrac{1}{2}\) - \(\dfrac{1}{5}\) = \(\dfrac{3}{10}\)
Bạn tự QĐMS nhé
\(\frac{1}{4}+\frac{3}{5}=\frac{17}{20}\)
\(\frac{5}{2}+\frac{7}{9}=\frac{59}{18}\)
\(\frac{3}{2}+\frac{2}{3}=\frac{13}{6}\)
\(\frac{4}{5}+\frac{3}{2}=\frac{23}{10}\)
\(\frac{4}{5}+\frac{3}{15}=\frac{4}{5}+\frac{1}{5}=1\)
\(\frac{2}{3}+\frac{32}{24}=\frac{2}{3}+\frac{4}{3}=2\)
\(\frac{5}{6}+\frac{15}{18}=\frac{5}{6}+\frac{5}{6}=\frac{10}{6}=\frac{5}{3}\)
\(\frac{8}{15}+\frac{2}{3}=\frac{8}{15}+\frac{10}{15}=\frac{18}{15}=\frac{6}{5}\)
\(\frac{3}{7}+\frac{4}{8}=\frac{24}{56}+\frac{28}{56}=\frac{52}{56}=\frac{13}{14}\)
_HT_
4/5 + 3/15 = 1 nhé
\(\frac{4}{5}+\frac{3}{15}=\frac{4}{5}+\frac{1}{5}=\frac{5}{5}=1\)
HT