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3/2 + 2/3 =...
4/5 + 3/2 =...
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NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
14 tháng 4 2023
( - \(\dfrac{4}{5}\) + \(\dfrac{2}{3}\)) + ( - \(\dfrac{5}{4}\) + \(\dfrac{14}{5}\) ) + ( \(\dfrac{7}{3}\) - 2)
= - \(\dfrac{4}{5}\) + \(\dfrac{2}{3}\) - \(\dfrac{5}{4}\) + \(\dfrac{14}{5}\) + \(\dfrac{7}{3}\) - 2
= ( \(\dfrac{14}{5}\) - \(\dfrac{4}{5}\)) + ( \(\dfrac{2}{3}\) + \(\dfrac{7}{3}\)) - \(\dfrac{5}{4}\) - 2
= \(\) 2 + 3 - \(\dfrac{5}{4}\) - 2
= ( 2 - 2) + ( 3 - \(\dfrac{5}{4}\))
= \(\dfrac{7}{4}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
4 tháng 11 2023
Bài 1:
a, 3\(\dfrac{2}{5}\) - \(\dfrac{1}{2}\)
= \(\dfrac{17}{5}\) - \(\dfrac{1}{2}\)
= \(\dfrac{34}{10}\) - \(\dfrac{5}{10}\)
= \(\dfrac{29}{10}\)
b, \(\dfrac{4}{5}\) + \(\dfrac{1}{5}\) x \(\dfrac{3}{4}\)
= \(\dfrac{4\times4}{5\times4}\) + \(\dfrac{1\times3}{5\times4}\)
= \(\dfrac{16}{20}\) + \(\dfrac{3}{20}\)
= \(\dfrac{19}{20}\)
c, 4\(\dfrac{4}{9}\) : 2\(\dfrac{2}{3}\) + 3\(\dfrac{1}{6}\)
= \(\dfrac{40}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{5}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{10}{6}\) + \(\dfrac{19}{6}\)
= \(\dfrac{29}{6}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
4 tháng 11 2023
Bài 2:
3\(\dfrac{2}{5}\) + 2\(\dfrac{1}{5}\)
= \(\dfrac{17}{5}\) + \(\dfrac{11}{5}\)
= \(\dfrac{28}{5}\)
b, 7\(\dfrac{1}{6}\) : 5\(\dfrac{2}{3}\)
= \(\dfrac{43}{6}\) : \(\dfrac{17}{3}\)
= \(\dfrac{43}{34}\)
3/2+2/3=9/6+4/6=13/6
4/5+3/2=8/10+15/10=23/10
\(\dfrac{3}{2}+\dfrac{2}{3}=\dfrac{9+4}{6}=\dfrac{13}{6}\)
\(\dfrac{4}{5}+\dfrac{3}{2}=\dfrac{8+15}{10}=\dfrac{23}{10}\)