11/20 và 6/8 ; 20/50 và 1/5
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\(A=\frac{3}{5}+6\frac{5}{6}.\left(11\frac{5}{20}-9\frac{1}{4}\right):8\frac{1}{3}\)
\(A=\frac{3}{5}+\frac{41}{6}.\left(\frac{23}{2}-\frac{37}{4}\right):\frac{25}{3}\)
\(A=\frac{3}{5}+\frac{41}{6}.\frac{9}{4}.\frac{3}{25}\)
\(A=\frac{3}{5}+\frac{41.9.3}{6.4.25}\)
\(A=\frac{3}{5}+\frac{41.3.3.3}{3.2.2.2.25}\)
\(A=\frac{3}{5}+\frac{41.9}{8.25}\)
\(A=\frac{3}{5}+\frac{369}{200}\)
\(A=\frac{489}{200}\)
Vậy \(A=\frac{489}{200}\)
\(A=\left(\frac{20}{5}+\frac{27}{9}\right)\times\frac{21}{10}=\left(4+3\right)\times\frac{21}{10}=7\times\frac{21}{10}=\frac{147}{10}\)
\(B=\left(\frac{13}{6}-\frac{3}{8}\right)\times\frac{11}{22}\)
\(B=\left(\frac{52}{24}-\frac{9}{24}\right)\times\frac{11}{22}\)
\(B=\frac{43}{24}\times\frac{1}{2}=\frac{43}{48}\)
Dễ thấy \(A=\frac{147}{10}>1\)
Mà \(B=\frac{43}{48}< 1\)
=> tự so sánh
a, = \(\dfrac{3}{4}\)x\(\dfrac{41}{24}\) = \(\dfrac{41}{32}\)
b, = \(\dfrac{1}{11}\) : \(\dfrac{1}{42}\) - \(\dfrac{20}{11}\) = \(\dfrac{42}{11}\) - \(\dfrac{20}{11}\) = \(\dfrac{22}{11}\) = 2
c, = \(\dfrac{26}{7}\) x 3 : \(\dfrac{1}{3}\) = \(\dfrac{78}{7}\) : \(\dfrac{1}{3}\) = \(\dfrac{234}{7}\)
Học tốt nhá
\(\dfrac{11}{20};\dfrac{6}{8}=\dfrac{3}{4}=\dfrac{3\times5}{4\times5}=\dfrac{15}{20}\)
Vì \(\dfrac{11}{20}< \dfrac{15}{20}\rightarrow\dfrac{11}{20}< \dfrac{6}{8}\)
\(\dfrac{20}{50}=\dfrac{2}{5};\dfrac{1}{5}\)
Vì \(\dfrac{2}{5}>\dfrac{1}{5}\rightarrow\dfrac{20}{50}>\dfrac{1}{5}\)
11/20;6/8=3/4=3×5/4×5=15/20
Vì 11/20<15/20→11/20<6/8
20/50=2/5;1/5
Vì 2/5>1/5=>20/50>1/5