\(\frac{x^2}{y-1}+\frac{y^2}{x-1}\ge2\sqrt{\frac{x^2}{y-1}.\frac{y^2}{x-1}}=2\sqrt{\frac{x^2}{x-1}.\frac{y^2}{y-1}}\ge2\sqrt{4.4}=8\)(cosi)
Vì \(\frac{x^2}{x-1}\ge4;\frac{y^2}{y-1}\ge4\)(vì \(\left(x-2\right)^2\ge0;\left(y-2\right)^2\ge0\))
dấu bằng xảy ra khi x=y=2