tìm x biết : 61*x=2806
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156 – ( x + 61) = 82
x + 61 = 156 – 82
x + 61 = 74
x = 74 – 61
x = 13.
\(4x=7y=3z\Rightarrow\dfrac{4x}{84}=\dfrac{7y}{84}=\dfrac{3z}{84}\\ \Rightarrow\dfrac{x}{21}=\dfrac{y}{12}=\dfrac{z}{28}=\dfrac{x+y+z}{21+12+28}=\dfrac{61}{61}=1\\ \Rightarrow\left\{{}\begin{matrix}x=21\\y=12\\z=28\end{matrix}\right.\)
\(\dfrac{x+35}{65}+\dfrac{x+39}{61}=\dfrac{x+43}{57}+\dfrac{x+47}{53}\)
\(\Leftrightarrow\dfrac{x+35}{65}+1+\dfrac{x+39}{61}+1=\dfrac{x+43}{57}+1+\dfrac{x+47}{53}+1\)
\(\Leftrightarrow\dfrac{x+100}{65}+\dfrac{x+100}{61}-\dfrac{x+100}{57}-\dfrac{x+100}{53}=0\)
\(\Leftrightarrow\left(x+100\right)\left(\dfrac{1}{65}+\dfrac{1}{61}-\dfrac{1}{57}-\dfrac{1}{53}\ne0\right)=0\Leftrightarrow x=-100\)
Ta có:
\(\dfrac{x+35}{65}+\dfrac{x+39}{61}=\dfrac{x+43}{57}+\dfrac{x+47}{53}\\ \Rightarrow\left(\dfrac{x+35}{65}+1\right)+\left(\dfrac{x+39}{61}+1\right)=\left(\dfrac{x+43}{57}+1\right)+\left(\dfrac{x+47}{53}+1\right)\\ \Rightarrow\dfrac{x+100}{53}+\dfrac{x+100}{61}=\dfrac{x+100}{57}+\dfrac{x+100}{53}\\ \Rightarrow\left(x+100\right)\left(\dfrac{1}{65}+\dfrac{1}{61}-\dfrac{1}{57}-\dfrac{1}{53}\right)=0\)
Ta thấy:
\(\dfrac{1}{65}< \dfrac{1}{57}\\ \dfrac{1}{61}< \dfrac{1}{53}\\ \Rightarrow\left(\dfrac{1}{65}+\dfrac{1}{62}\right)-\left(\dfrac{1}{57}+\dfrac{1}{53}\right)< 0\)
Hay \(\dfrac{1}{65}+\dfrac{1}{62}-\dfrac{1}{57}-\dfrac{1}{53}\ne0\)
\(\Rightarrow x+100=0\\ \Rightarrow x=0-100\\ \Rightarrow x=-100\)
Vậy \(x=-100\)
a) 467 + x = 877 – 162
467 + x = 715
x = 715 – 467
x = 248
b) x – 214 = 61 + 345
x – 214 = 406
x = 406 + 214
x = 620
c) x : 5 = 10 × 2
x : 5 = 20
x = 20 × 5
x = 100
d) x × 4 = 30 – 10
x × 4 = 20
x = 20 : 4
x = 5
a) 156 - ( x + 61 ) = 82
x + 61 = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
b) 124 + ( 18 - x ) = 317
18 - x = 317 - 124
18 - x = 193
x = 18 - 193
x = -175
61*x=2806
x=2806 : 61
x=46
x= 2806 : 61