25 : 8 =17 phải không aj
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\(a)\dfrac{5}{8}+\dfrac{3}{17}+\dfrac{4}{18}+21\)
\(=\dfrac{5}{8}+\dfrac{3}{17}+\dfrac{2}{9}+21\)
\(=\dfrac{109}{136}+\dfrac{191}{9}\)
\(=\dfrac{26957}{1224}\)
\(b)\dfrac{25}{20}-\dfrac{18}{13}+5+\dfrac{5}{13}\)
\(=\dfrac{5}{4}-\dfrac{18}{13}+5+\dfrac{5}{13}\)
\(=\dfrac{-7}{52}+\dfrac{70}{13}\)
\(=\dfrac{21}{4}\)
a) 189 : 3 x 8 > 189 : 9 x 8
b) 25 x 17 > 27 x 15
k mk nha
`@` `\text {Ans}`
`\downarrow`
`x^3 = 125`
`=> x^3 = 5^3`
`=> x = 5`
Vậy, `x = 5`
_____
`4^5 \div 4^3`
`=`\(4^{5-3}\)
`= 4^2`
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\(8^{12}\cdot8^3\div8^{15}\)
`=`\(8^{12+3-15}\)
`=`\(8^0=1\)
______
\(7^{15}\div7^{13}\)
`=`\(7^{15-13}\)
`=`\(7^2\)
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\(17^{15}\cdot17^{10}\div17^{22}\)
`=`\(17^{15+10-22}\)
`= 17^3`
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\(5^{10}\cdot25\div5^{11}\)
`=`\(5^{10}\cdot5^2\div5^{11}\)
`=`\(5^{10+2-11}\)
`= 5`
_______
\(15^{10}\cdot225\div15^{11}\)
`=`\(15^{10}\cdot15^2\div15^{11}\)
`=`\(15^{12}\div15^{11}\)
`= 15`
`@` `\text {Kaizuu lv uuu}`
\(x^3=125\)
\(\Rightarrow x^3=5^3\)
\(\Rightarrow x=3\)
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\(4^5:4^3\)
\(=4^{5-3}\)
\(=4^2=16\)
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\(8^{12}.8^3:8^{15}\)
\(=8^{15}:8^{15}\)
\(=1\)
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\(7^{15}:7^{13}\)
\(=7^{15-13}\)
\(=7^2=49\)
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\(17^{15}.17^{10}:17^{22}\)
\(=17^{25}:17^{22}\)
\(=17^3=4913\)
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\(5^{10}.25:5^{11}\)
\(=5^{10}.5^2:5^{11}\)
\(=5^{12}:5^{11}\)
\(=5^1=5\)
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\(15^{10}.225:15^{11}\)
\(=15^{10}.15^2:15^{11}\)
\(=15^{12}:15^{11}\)
\(=15^1=15\)
__________________
* an . am = an+m
an : am = an-m
Chúc bạn học tốt
Vậy để lấy lấy không ít hơn 8 viên bi cùng màu là
7+7+7+7+1=29 (viên bi)
ĐS: 29 viên bi
Phải lấy ra ít nhất 76 viên bi.
100% là đúng!Mình thi Violimpic toán rồi!k nha!
\(-\dfrac{3}{16}+-\dfrac{3}{8}-\dfrac{5}{4}\)
\(=-\dfrac{3}{16}-\dfrac{3}{8}-\dfrac{5}{4}\)
\(=-\dfrac{3}{16}-\dfrac{6}{16}-\dfrac{20}{16}\)
\(=\dfrac{-3-6-20}{16}\)
\(=-\dfrac{29}{16}\)
\(\left(-\dfrac{25}{13}\right)+\dfrac{-9}{17}+\dfrac{12}{13}+\dfrac{25}{17}\)
\(=\left[\left(-\dfrac{25}{13}\right)+\dfrac{12}{13}\right]+\left[\left(-\dfrac{9}{17}+\dfrac{25}{17}\right)\right]\)
\(=-\dfrac{13}{13}+\dfrac{17}{17}\)
\(=-1+1\)
\(=0\)
25 : 8 = 17 là sai nhé !
25 : 8 = 3 dư 1
em cảm ơn chị nhé