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11 tháng 2 2022

\(\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{3}{7}\right)\times\left(1-\dfrac{3}{10}\right)\times\left(1-\dfrac{3}{97}\right)\times\left(1-\dfrac{3}{100}\right)\)

\(=\dfrac{2}{3}\times\dfrac{4}{7}\times\dfrac{7}{10}\times...\times\dfrac{94}{97}\times\dfrac{97}{100}\)

\(=\dfrac{2\times4\times7\times...\times94\times97}{3\times7\times10\times...\times97\times100}\)

\(=\dfrac{2\times4}{3\times100}=\dfrac{8}{300}=\dfrac{2}{75}\)

\(A=\dfrac{2}{3}\cdot\dfrac{4}{7}\cdot\dfrac{7}{10}\cdot...\cdot\dfrac{94}{97}\cdot\dfrac{97}{100}=\dfrac{2}{3}\cdot\dfrac{1}{25}=\dfrac{2}{75}\)

17 tháng 6 2021

Các anh các cj giúp em nhé 
Em cảm ơn trước

Giải:

a) \(\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right).\left(1-\dfrac{1}{5}\right)\) 

\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}\) 

\(=\dfrac{1.2.3.4}{2.3.4.5}\) 

\(=\dfrac{1}{5}\) 

b) \(\left(1-\dfrac{3}{4}\right).\left(1-\dfrac{3}{7}\right).\left(1-\dfrac{3}{10}\right).\left(1-\dfrac{3}{13}\right).....\left(1-\dfrac{3}{97}\right).\left(1-\dfrac{3}{100}\right)\) 

\(=\dfrac{1}{4}.\dfrac{4}{7}.\dfrac{7}{10}.\dfrac{10}{13}.....\dfrac{94}{97}.\dfrac{97}{100}\) 

\(=\dfrac{1.4.7.10.....94.97}{4.7.10.13.....97.100}\) 

\(=\dfrac{1}{100}\) 

Chúc bạn học tốt!

21 tháng 12 2022

`a)(1-1/2)xx(1-1/3)xx(1-1/4)xx(1-1/5)`

`=1/2xx2/3xx3/4xx4/5`

`=[1xx2xx3xx4]/[2xx3xx4xx5]`

`=1/5`

`b)(1-3/4)xx(1-3/7)xx(1-3/10)xx(1-3/13)xx .... xx(1-3/97)xx(1-3/100)`

`=1/4xx4/7xx7/10xx10/13xx .... xx94/97xx97/100`

`=[1xx4xx7xx10xx...xx94xx97]/[4xx7xx10xx13xx....xx97xx100]`

`=1/100`

28 tháng 5 2019

#)Giải :

\(\left(1-\frac{3}{4}\right)x\left(1-\frac{3}{7}\right)x\left(1-\frac{3}{10}\right)x\left(1-\frac{1}{13}\right)x...x\left(1-\frac{3}{100}\right)\)

\(=\frac{1}{4}x\frac{4}{7}x\frac{7}{10}x...x\frac{94}{97}x\frac{97}{100}\)

\(=\frac{1x4x7x...x94x100}{4x7x10x...x97x100}\)

\(=\frac{1}{100}\)

           #~Will~be~Pens~#

28 tháng 5 2019

\(\left(1-\frac{3}{4}\right)\left(1-\frac{3}{7}\right)\left(1-\frac{3}{10}\right)\left(1-\frac{1}{13}\right)...\left(1-\frac{1}{97}\right)\left(1-\frac{3}{100}\right)\)

\(=\frac{1}{4}.\frac{4}{7}.\frac{7}{10}.\frac{10}{13}...\frac{94}{97}.\frac{97}{100}\)

\(=\frac{1}{100}\)

Giải:

\(\left(1-\dfrac{3}{4}\right).\left(1-\dfrac{3}{7}\right).\left(1-\dfrac{3}{10}\right).\left(1-\dfrac{3}{13}\right).....\left(1-\dfrac{3}{97}\right).\left(1-\dfrac{3}{100}\right)\) 

\(=\dfrac{1}{4}.\dfrac{4}{7}.\dfrac{7}{10}.\dfrac{10}{13}.....\dfrac{94}{97}.\dfrac{97}{100}\) 

\(=\dfrac{1.4.7.10.....94.97}{4.7.10.13.....97.100}\) 

\(=\dfrac{1}{100}\)

25 tháng 11 2017

( 1 - 3/4 ) x ( 1 - 3/7 ) x ( 1 - 3/10 ) x ( 1 - 3/13 ) x ......x ( 1 - 3/97 ) x ( 1 - 3/100 ) . 

= 1/4 x 4/7 x 7/10 x ... x 97/100 . 

Khử đi các số giống nhau . 

= 1/100 nha bạn . 

25 tháng 11 2017

1 − 4 3 1 − 7 3 1 − (10 3 ... 1 − 97 3 1 − 100 3 = 4 1 . 7 4 . 10 7 ..... 97 94 . 100 97 = 4.7.10.....97.100 1.4.7.....94.97 = 100 1 

12 tháng 7 2016

\(\left(1-\frac{3}{4}\right)x\left(1-\frac{3}{7}\right)x\left(1-\frac{3}{10}\right)x\left(1-\frac{3}{13}\right)x...x\left(1-\frac{3}{97}\right)x\left(1-\frac{3}{100}\right)\)

\(=\frac{1}{4}x\frac{4}{7}x\frac{7}{10}x\frac{10}{13}x...x\frac{94}{97}x\frac{97}{100}\)

\(=\frac{1}{100}\)

12 tháng 7 2016

\(\left(1-\frac{3}{4}\right)\times\left(1-\frac{3}{7}\right)\times\left(1-\frac{3}{10}\right)...\times\left(1-\frac{3}{97}\right)\times\left(1-\frac{3}{100}\right)\)

\(=\frac{1}{4}\times\frac{4}{7}\times\frac{7}{10}\times...\times\frac{94}{97}\times\frac{97}{100}\)

\(=\frac{1\times4\times7\times10\times...\times97}{1\times4\times7\times10\times...\times97\times100}\)

\(=\frac{1}{100}\)

10 tháng 4

Bài 1 

a; \(\dfrac{7}{19}\) x \(\dfrac{1}{3}\) + \(\dfrac{7}{19}\) x \(\dfrac{2}{3}\)

\(\dfrac{7}{19}\) x (\(\dfrac{1}{3}+\dfrac{2}{3}\))

\(\dfrac{7}{19}\) x 1

\(\dfrac{7}{19}\)

10 tháng 4

b; 15 x \(\dfrac{2121}{4343}\) + 15 x \(\dfrac{212121}{434343}\)

= 15 x \(\dfrac{21}{43}\) + 15 x \(\dfrac{21}{43}\)

= 15 x \(\dfrac{21}{43}\) x (1 + 1)

= 15 x \(\dfrac{21}{43}\) x 2

= (15 x 2) x \(\dfrac{21}{43}\)

= 30 x \(\dfrac{21}{43}\)

\(\dfrac{630}{43}\)

21 tháng 7 2017

Câu 1:  \(\frac{5}{7}\):x+\(\frac{2}{3}\)=1\(\frac{1}{3}\)

\(\frac{5}{7}\):x+\(\frac{2}{3}\)=\(\frac{4}{3}\)

\(\frac{5}{7}\):x=\(\frac{4}{3}\)  -    \(\frac{2}{3}\)

\(\frac{5}{7}\):x=\(\frac{2}{3}\)

x=\(\frac{5}{7}\):\(\frac{2}{3}\)

x=\(\frac{15}{14}\)

Câu 2:x*\(\frac{3}{7}\)-\(\frac{5}{14}\)=2\(\frac{1}{3}\)

x*\(\frac{3}{7}\)-\(\frac{5}{14}\)=\(\frac{7}{3}\)

x*\(\frac{3}{7}\)=\(\frac{7}{3}\)+\(\frac{5}{14}\)

x*\(\frac{3}{7}\)=\(\frac{113}{42}\)

x=\(\frac{113}{42}\):\(\frac{3}{7}\)

x=\(\frac{791}{126}\)

Câu 3:  3\(\frac{5}{7}\)-x*\(\frac{1}{3}\)=1\(\frac{13}{11}\)

\(\frac{26}{7}\)-x*\(\frac{1}{3}\)=\(\frac{24}{11}\)

x*\(\frac{1}{3}\)=\(\frac{26}{7}\)-\(\frac{24}{11}\)

x*\(\frac{1}{3}\)=\(\frac{118}{77}\)

x=\(\frac{118}{77}\):\(\frac{1}{3}\)

x=\(\frac{356}{77}\)