đề bài:tính 84dm+0m=?dm
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8 x 10 x 12 x 14 x 16 x 18 x 20 x (1,25 x 2 x 5 x 0,5)
= 8 x 10 x 12 x 14 x 16 x 18 x 20 x 1,25 x 2 x 5 x 0,5
= (1,25 x 8) x (20 x 0,5) x ( 2 x 5) x 12 x 14 x 16 x 18
= 10 x 10 x 100 x 48384
= 483840000
25dam x 2 = 50dam 48m : 4 = 12m
18hm x 4 = 72hm 84dm : 2 = 42dm
82km x 5 = 410km 66mm : 6 = 11mm
13,25 :0,5 +13,25 :0,25 +13,25 :0,125
= 13,25 x 2 +13,25 x 4 +13,25 x 8
= 13,25 x ( 2 + 4 + 8 )
=13,25 x 14 = 185,5
= 13,25 nhân 2 + 13,25 nhân 4 = 13 , 25 nhân 8
=13,25 nhân [ 2 + 4 + 8]
=13,25 nhân 14
=185,5
Đề bài:tính bằng cách thuật tiện nhất.(Biết A+B+C=20,19)
45,54.B+67,76.A+89,98.C+32,24.A+10,02.C+54.46.B
= B.(45,54 + 54,46) + A.(67,76 + 32,24) + C.(89,98 + 10,02)
= B.100 + A.100 + C.100
= 100.(A + B + C)
= 100.20,19
= 2019
A = 1/1x2 +1/2x3+1/3x4+1/4x5+1/5x6+1/6x7+1/7x8
=1-1/2+1/2-1/3+1/3-1/4+..+1/7-1/8
=1-1/8
=7/8
a, ( 3 - 0,6) - ( 7 + 3\(\dfrac{1}{4}\) - \(\dfrac{8}{5}\)) - ( 9 - 2\(\dfrac{1}{4}\))
= 2,4 - (7 + 3,25 - 1,6) - (9 - 2,25)
= 2,4 - 7 - 3,25 + 1,6 - 9 + 2,25
= (2,4 + 1,6) - (7+ 9) - ( 3,25 - 2,25)
= 4 - 16 - 1
= - 12 - 1
= -13
b, ( - \(\dfrac{5}{8}\) + \(\dfrac{7}{6}\) - \(\dfrac{0}{8}\)) - (\(\dfrac{5}{6}\) - \(\dfrac{7}{8}\) - 1,4) + ( \(\dfrac{3}{4}\) + \(\dfrac{5}{3}\) + \(\dfrac{12}{5}\))
= - \(\dfrac{5}{8}\) + \(\dfrac{7}{6}\) - \(\dfrac{5}{6}\) + \(\dfrac{7}{8}\) + \(\dfrac{7}{5}\) + \(\dfrac{3}{4}\) + \(\dfrac{5}{3}\) + \(\dfrac{12}{5}\)
= (- \(\dfrac{5}{8}\) + \(\dfrac{7}{8}\)) + (\(\dfrac{7}{6}\) - \(\dfrac{5}{6}\)) + ( \(\dfrac{7}{5}\) + \(\dfrac{12}{5}\)) + \(\dfrac{3}{4}\) + \(\dfrac{5}{3}\)
= \(\dfrac{1}{4}\) + \(\dfrac{1}{3}\) + \(\dfrac{19}{5}\) + \(\dfrac{3}{4}\) + \(\dfrac{5}{3}\)
= (\(\dfrac{1}{4}\) + \(\dfrac{3}{4}\)) + ( \(\dfrac{1}{3}\) + \(\dfrac{5}{3}\)) + \(\dfrac{19}{5}\)
= 1 + 2 + 3,8
= 6,8
\(45,54B+67,76A+89,98C+32,24A+10,02C+54,46B\)
\(=100A+100B+100C\)
\(=100\left(A+B+C\right)\)
\(=100.20,19\)
\(=2019\)
bằng 84 dm
=84 dm