mấy bạn viết jum mink vs ( thi nói SPEAKING ) LỚP 8
Topic: A vacation abroad
HELP ME ! PLEASE!!!!!!
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SM
2
HA
25 tháng 12 2016
Reading books :
I'm very happy to introduce somethings about the activity I do in my free time. I often read books in my free time. I started reading books when I was at the age of six. You know that, I have known how to read books. I read whatever I saw and whenever I had free time. I often went to library or bookshop to find some interesting books and I bought it. Now, I have a large colection of books. I often find out the most interesting of the books give us and share to my sister. I found it very useful. I love reading books a lot and I hope, I will keep doing this activity in the future.
25 tháng 12 2016
There are three activities I like to do in my free time. The first is cartoon. I like watch cartoons very much. I love “Total Spies” most because it is very exciting and funny. I often watch it with my friends to relax. Second, I also play football with my brother and my friends when I have free time. I often play it in our school yard. I think playing football is sport which helps us have good health and study better. Final, I like reading books best. Since reading books are good, you can learn about another culture and again your knowledge. Moreover, it is a form of entertainment, which is useful to our life. All in all, I find that if I haven’t anything to do in my free time, I will be boring. Therefore, you should also choose some activities for yourself to do, which helps you have healthy way of life.
Nếu rùi thì cho mink biết đề Tập làm văn vs nha
....Bn nào cho mink bt thì mink sẽ like và theo dõi nick của bn ấy...
HELP ME, PLEASE....
PT
23 tháng 3 2017
Đề 1: Nhân dân ta thường nhắc nhở nhau: Ăn quả nhớ kẻ trồng cây. Hãy chứng minh lời nhắc nhở đó là nét đẹp truyền thống đạo lí của dân tộc Việt Nam
Đề 2:Viết một bài văn nghị luận giải thích câu tục ngữ: “Lá lành đùm lá rách”.
MT
15 tháng 1 2016
\(\frac{6}{x^2+2}+\frac{12}{x^2+8}=3-\frac{7}{x^2+3}\)
\(\Leftrightarrow\frac{6}{x^2+2}-1+\frac{12}{x^2+8}-1=1-\frac{7}{x^2+3}\)
\(\Leftrightarrow\frac{6}{x^2+2}-\frac{x^2+2}{x^2+2}+\frac{12}{x^2+8}-\frac{x^2+8}{x^2+8}=\frac{x^2+3}{x^2+3}-\frac{7}{x^2+3}\)
\(\Leftrightarrow\frac{-x^2+4}{x^2+2}+\frac{-x^2+4}{x^2+8}=\frac{x^2-4}{x^2+3}\)
\(\Leftrightarrow\frac{-x^2+4}{x^2+2}+\frac{-x^2+4}{x^2+8}+\frac{-x^2+4}{x^2+3}=0\)
\(\Leftrightarrow\left(-x^2+4\right)\left(\frac{1}{x^2+2}+\frac{1}{x^2+8}+\frac{1}{x^2+3}\right)=0\)
\(\Leftrightarrow-x^2+4=0\left(\text{vì : }\frac{1}{x^2+2}+\frac{1}{x^2+8}+\frac{1}{x^2+3}\ne0\right)\)
<=>(2-x)(2+x)=0
<=>x=2 hoặc x=-2
Vậy S={-2;2}
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