A = 2004 x 2006 + 10
2005x2005+9
K
Khách
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22 tháng 10 2019
a)=(3/8+10/16)+(7/12+10/24)
=1+1=2
c)=(4/6+14/6)+(7/13+19/13)+(17/9+1/9)
=3+2+2=7
HT
18 tháng 4 2017
\(\frac{2006\times2004-9}{1995+2004\times2005}=\frac{\left(2005+1\right)\times2004-9}{1995+2004\times2005}\)
\(=\frac{2005\times2004+2004-9}{2004\times2005+1995}\)
\(=\frac{2005\times2004+1995}{1995+2004\times2005}\)
\(=1\)
18 tháng 4 2017
2006x 2004 -9/1995 +2004x 2005
=(2005+1)x2004 -9/1995+2004x2005
=2005x2004+2004 x1-9/1995+2005x2004
=2005x2004+2004-9/1995+2004x2005
=2005x2004+1995/1995+2005x2004
=1
MM
15 tháng 8 2018
\(2004\)x\(2006-\frac{2003}{2005}\)x\(2005-2004\)
\(=2004\)x\(2006-\frac{2003}{2005}\)x\(\frac{2005}{1}-2004\)
\(=2004\)x\(2006-2003-2004\)
\(=2006-2003\)
\(=3\)
15 tháng 8 2018
2004 x 2006 - 2003 / 2005 x 2005 - 2004
= 2004 x ( 2005 + 1 ) - 2003 / ( 2004 + 1 ) x 2005 - 2004
= 2004 x 2005 + 2004 x 1 - 2003 / 2004 x 2005 + 1 x 2005 - 2004
= 2004 x 2005 + 2004 - 2003 / 2004 x 2005 + 2005 - 2004
= 2004 x 2005 + 1 / 2004 x 2005 + 1
= 1 / 1 = 1
Nếu có sai chỗ nào thì chỉ mk nha !
Hok tốt !
KT
13 tháng 2 2018
a) \(\frac{x+1}{4}-\frac{x+2}{5}+\frac{x+4}{7}-\frac{x+5}{8}+\frac{x+7}{10}-\frac{x+9}{12}=0\)
\(\Leftrightarrow\)\(\frac{x+1}{4}-1-\frac{x+2}{5}+1+\frac{x+4}{7}-1-\frac{x+5}{8}+1+\frac{x+7}{10}-1-\frac{x+9}{12}+1=0\)
\(\Leftrightarrow\)\(\frac{x-3}{4}-\frac{3-x}{5}+\frac{x-3}{7}-\frac{3-x}{8}+\frac{x+3}{10}-\frac{3-x}{12}=0\)
\(\Leftrightarrow\)\(\frac{x-3}{4}+\frac{x-3}{5}+\frac{x-3}{7}+\frac{x-3}{8}+\frac{x-3}{10}+\frac{x-3}{12}=0\)
\(\Leftrightarrow\)\(\left(x-3\right)\left(\frac{1}{4}+\frac{1}{5}+\frac{1}{7}+\frac{1}{8}+\frac{1}{10}+\frac{1}{12}\right)=0\)
Vì \(\frac{1}{4}+\frac{1}{5}+\frac{1}{7}+\frac{1}{8}+\frac{1}{10}+\frac{1}{12}\ne0\)
\(\Rightarrow\)\(x-3=0\)
\(\Leftrightarrow\)\(x=3\)
Vậy...
b) \(\frac{x}{2004}+\frac{x+1}{2005}+\frac{x+2}{2006}+\frac{x+3}{2007}=4\)
\(\Leftrightarrow\)\(\frac{x}{2004}-1+\frac{x+1}{2005}-1+\frac{x+2}{2006}-1+\frac{x+3}{2007}-1=0\)
\(\Leftrightarrow\)\(\frac{x-2004}{2004}+\frac{x-2004}{2005}+\frac{x-2004}{2006}+\frac{x-2004}{2007}=0\)
\(\Leftrightarrow\)\(\left(x-2004\right)\left(\frac{1}{2004}+\frac{1}{2005}+\frac{1}{2006}+\frac{1}{2007}\right)=0\)
Vì \(\frac{1}{2004}+\frac{1}{2005}+\frac{1}{2006}+\frac{1}{2007}\ne0\)
\(\Rightarrow\)\(x-2004=0\)
\(\Leftrightarrow\)\(x=2004\)
Vậy...
31 tháng 7 2015
\(\frac{2006\times2004-9}{2004\times2005+1995}=\frac{2005\times2004+2004-9}{2004\times2005+1995}=\frac{2005\times2004+1995}{2004\times2005+1995}=1\)
DT
0
1 tháng 7 2016
a) \(C=x^3+3x^2+3x+10=\left(x+1\right)^3+9\)
Tại x = 99...9 (2004 chữ số 9) thì: x+1 = 100...0 (2004 chữ số 0) = 102004
Khi đó, C = (102004)3 + 9 = 106012 + 9.
b) \(B=\left(5x-11\right)^2-\left(10x-22\right)\left(5x-9\right)+\left(5x-9\right)^2=\)
\(=\left(5x-11\right)^2-2\cdot\left(5x-11\right)\left(5x-9\right)+\left(5x-9\right)^2=\left(5x-11-\left(5x-9\right)\right)^2=\left(-2\right)^2=4\)
Hay B = 4 với mọi x .
Vậy tại x = 20052006 thì B = 4.
\(A=\frac{2004x2006+10}{2005x2005+9}=\frac{2004x2005+2004+10}{2004x2005+2005+9}=\frac{2004x2005+2014}{2004x2005+2014}=1\)
2004x2006+10=4020034
2005x2005+9=4020034