Tính nhanh:a) \(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)\)
b)\(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)
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\(=\)\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right)\times\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)
\(=\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right)\times0\)
\(=0\)
\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)\)
=\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)
=\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{1}{12}-\frac{1}{12}\right)\)
=\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).0\)
=0
ve 2 bang 0
con ve 1 o can tinh du co lon
vi 0 nhan bao nhieu cung bang o
C=(67/111+2/33-15/117).(1/3-1/4-1/12)
C=(67/111+2/33-15/117).0
C=0
MK NHA MK NHANH NHẤT ĐÓ
1) \(5\frac{2}{7}\).\(\frac{8}{11}\)+\(5\frac{2}{7}.\frac{5}{11}+5\frac{2}{7}.\frac{-2}{11}\)
= \(5\frac{2}{7}\).[\(\frac{8}{11}+\frac{5}{11}+\frac{-2}{11}\)]
= \(5\frac{2}{7}\).1
=\(5\frac{2}{7}\)
2)
5 2/7.8/9+5 2/7.5/11-5 2/7.2/11
=5 2/7.(8/11+5/11+2/11)
=5 2/7.15/11
=240/77.
(67/111+2/33-15/117).(1/3-1/4-1/12)
=811/1221.1/12
=811/14652
\(\frac{2^3.5.7.5^2.7^3}{2^2.5^2.7^4}=\frac{2^3.5^3.7^4}{2^2.5^2.7^4}=2.5=10\)
đối với lớp 6 thì trình bày thế này dễ hiểu hơn
\(\frac{\left(2^3.5.7\right)\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}=\frac{2^3.5.5^2.7.7^3}{2.5.7^2.2.5.7^2}=\frac{2^3.5^3.7^4}{2^2.5^2.7^4}=\frac{2.5}{1}=10\)
c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)