11.x- 7.x+x=325
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\(\frac{22}{25}\times\frac{5}{11}-\frac{33}{25}:\frac{11}{5}+\frac{58}{11}\)
\(=\frac{22}{25}\times\frac{5}{11}-\frac{33}{25}\times\frac{5}{11}+\frac{58}{11}\)
\(=\frac{5}{11}\times\left(\frac{22}{25}+\frac{33}{25}\right)+\frac{58}{11}\)
\(=\frac{5}{11}\times\frac{11}{5}+\frac{58}{11}\)
\(=1+\frac{58}{11}\)
\(=\frac{11}{11}+\frac{58}{11}\)
\(=\frac{69}{11}\)
\(8\frac{3}{11}-\left(3\frac{5}{7}-7\frac{8}{11}\right)\)
\(=\frac{91}{11}-\left(\frac{26}{7}-\frac{85}{11}\right)\)
\(=\frac{91}{11}-\frac{26}{7}+\frac{85}{11}\)
\(=\frac{91}{11}+\frac{85}{11}-\frac{26}{7}\)
\(=16-\frac{26}{7}\)
\(=\frac{86}{7}\)
\(\frac{5}{6}x+325\%=\frac{3}{2}x-30,75\)
\(=>\frac{5}{6}x+3,25=\frac{3}{2}x-30,75\)
\(=>\frac{5}{6}x-\frac{3}{2}x=-30,75-3,25\)
\(=>\frac{-2}{3}x=-34\)
\(=>x=-34:\left(-\frac{2}{3}\right)\)
\(=>x=-34.\left(\frac{3}{-2}\right)\)
\(=>x=51\)
\(325\times11-32500\times0,1-325\)
\(=325\times11-325\times100\times0,1-325\)
\(=325\times\left(11-100\times0,1-1\right)\)
\(=325\times\left(11-10-1\right)\)
\(=325\times0=0\)
11x - 7x + x=325
=> x.(11-7+1)=325
=> x.5 =325
=> x=325 : 5
=> x = 65
x. 11- x. 7+ x= 325.
x. 11- x. 7+ x. 1= 325.
x( 11- 7+ 1)= 325.
x. 5= 325.
x= 325: 5.
x= 65.
Vậy x= 65.
a) ( x : 273 ) - 946 = 754
x : 273 = 754 + 946
x : 273 = 1700
x = 1700 x 273
x = 464100
b) ( 325 - x ) : 11 = 18
325 - x = 18 x 11
325 - x = 198
x = 325 - 198
x = 127
420: x + 27 . 11= 325
420:x+297=325
420:x=28
x=420:28
x=15
Vậy x=15
420: x+ 27. 11= 325
=> 420: x+ 297= 325
=> 420: x= 325- 297
=> 420: x= 28
=> x= 420: 28
=> x= 15
Vậy x= 15
A tính theo công thức tính tổng dãy số cách đều có khoảng cách là 3 (cấp số cộng có d=3)
\(3C=2x3x3+3x4x3+4x5x3+5x6x3+...x199x200x3+200x201x3\)
\(3C=2x3x\left(4-1\right)+3x4x\left(5-2\right)+4x5x\left(6-3\right)+...+200x201\left(202-199\right)\)
3C=--1x2x3+2x3x4-2x3x4+3x4x5-3x4x5+4x5x6-...-199x200x201+200x201x202
3C=200x201x202-1x2x3=> C=(200x201x202-1x2x3):3=200x67x202-2
y + 576 × 11 - 325 = 45897
y + 6336 = 45897 + 325
y + 6336 = 46222
=> y = 46222 - 6336
=> y = 39886
Vậy y = 39886
y + 576 x 11 - 325 = 45897
y + 6336 - 325 = 45897
y + 6011 = 45897
y = 45897 - 6011
y = 39886
Vậy y = 39886
Nhớ k cho mình nhé! Thank you!!!
a,
\(\frac{326}{325}-\frac{1}{325}=1\) \(\frac{325}{324}-\frac{1}{324}=1\)
Vì \(\frac{1}{325}< \frac{1}{324}\)nên \(\frac{326}{325}< \frac{325}{324}\)
b,
( 11 x 9 - 900 x 0,1 - 8 ) x ( 56,7 x 0,5 + 56,7 x 9,5 )
= ( 99 - 90 - 8 ) x [ 56,7 x ( 0,5 + 9,5 ) ]
= ( 9 - 8 ) x ( 56,7 x 10 )
= 1 x 567 = 567
\(325-3.\left(x-7\right)=169:13\)
\(325-3.\left(x-7\right)=13\)
\(3.\left(x-7\right)=325-13\)
\(3.\left(x-7\right)=312\)
\(x-7=312:3\)
\(x-7=104\)
\(x=104+7\Rightarrow x=111\)
11.x-7.x+x=325
x=x.(11-7+1)=325
x=x.5=325
x=325:5
x=65