A. 5 mũ 10
B. 10 mũ 20
C. 5 mũ 75
D. 5 mũ 20
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\(a,27^4\cdot81^{10}=\left(3^3\right)^4\cdot\left(3^4\right)^{10}=3^{12}\cdot3^{40}=3^{52}\\ b,=8^{31}\cdot32^5:64^4=\left(2^3\right)^{31}\cdot\left(2^5\right)^5:\left(2^6\right)^4=2^{93}\cdot2^{25}:2^{24}=2^{93+25-24}=2^{94}\)
a)\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{-5}{9}\)
b)\(\frac{\left(-11\right)^5.13^7}{11^5.13^8}=-\frac{1}{13}\)
c)\(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.3^9\left(3-1\right)}{2^9.3^{10}}=2\)
d(\(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.7^{11}\left(7+1\right)}{5^{11}.7^{11}\left(35+9\right)}=\frac{1}{6}\)
a: \(=\dfrac{-3^{10}\cdot5^{21}}{5^{20}\cdot3^{12}}=\dfrac{-5}{3^2}=-\dfrac{5}{9}\)
b: \(=\dfrac{-11^5\cdot13^7}{11^5\cdot13^8}=-\dfrac{1}{13}\)
a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
Câu 1.9920và 999910
=(992)10=980110
Vậy 980110<999910 suy ra 9920<999910
Câu 2. 3500và 7300
3500=(35)100=243100
7300=(73)100=343100
Vậy 243100<343100 => 3500<7300
a: \(=\dfrac{-3^{10}\cdot5^{21}}{5^{20}\cdot3^{12}}=-\dfrac{5}{9}\)
b: \(=\dfrac{-11^5\cdot13^7}{11^5\cdot13^8}=\dfrac{-1}{13}\)
c: \(=2^{10}\cdot3^{10}-2^{10}\cdot3^9=2^{10}\cdot3^9\cdot\left(3-1\right)=2^{11}\cdot3^9\)
\(5^{12}.7-5^{11}.10\)
\(=5^{11}.\left(5.7-10\right)\)
\(=5^{11}.25\)
\(=5^{11}.5^2\)
\(=5^{13}\)
\(2^{20}.15+2^{20}.85\)
\(=2^{20}.5\left(3+17\right)\)
\(=2^{20}.100\)
\(=104857600\)
\(125^3:25^4\)
\(=\left(5^3\right)^3:\left(5^2\right)^4\)
\(=5^9:5^8\)
\(=5\)
\(24^4:3^4-32^{12}:16^{12}\)
\(=\left(24:3\right)^4-\left(32:16\right)^{12}\)
\(=8^4-2^{12}\)
\(=0\)
D
D