Tìm x biết x+150=980:\(\frac{5}{4}\)+\(\frac{-4}{5}\)
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1311/10= 4/5 + 4/5+5/4 +5/4 + 64 + 3x
1311/10 = 681/10 + 3x
1311/10 - 681/10 = 3x
630/10 = 3x
=> x = 630/10 :3
x= 21
\(\frac{x+4}{5}+\frac{x+2}{7}=\frac{x+5}{4}+\frac{x+7}{2}\)
\(\Rightarrow\left(\frac{x+4}{5}+1\right)+\left(\frac{x+2}{7}+1\right)=\left(\frac{x+7}{2}+1\right)+\left(\frac{x+2}{7}+1\right)\)
\(\Rightarrow\frac{x+9}{5}+\frac{x+9}{7}=\frac{x+9}{4}+\frac{x+9}{2}\)
\(\Rightarrow\frac{x+9}{2}+\frac{x+9}{4}-\frac{x+9}{7}-\frac{x+9}{5}=0\)
\(\Rightarrow\left(x+9\right)\left(\frac{1}{2}+\frac{1}{4}-\frac{1}{5}-\frac{1}{7}\right)=0\)
vì \(\frac{1}{2}+\frac{1}{4}-\frac{1}{5}-\frac{1}{7}\ne0\Rightarrow x+9=0\)
=>x=-9
vậy x=-9
\(\frac{2}{3}\left(\frac{3}{5}x+\frac{1}{2}\right)=\frac{4}{5}\left(\frac{5}{6}x-\frac{4}{3}\right)+\frac{1}{2}x-\frac{4}{5}\)
\(\frac{2}{5}x+\frac{1}{3}=\frac{2}{3}x-\frac{16}{15}+\frac{1}{2}x-\frac{4}{5}\)
\(\frac{2}{5}x-\frac{2}{3}x-\frac{1}{2}x=-\frac{16}{15}-\frac{4}{5}-\frac{1}{3}\)
\(\left(\frac{2}{5}-\frac{2}{3}-\frac{1}{2}\right)x=-\frac{16}{15}-\frac{12}{15}-\frac{5}{15}\)
\(\left(\frac{12}{30}-\frac{20}{30}-\frac{15}{30}\right)x=-\frac{33}{15}\)
\(\frac{-23}{30}x=-\frac{33}{15}\)
\(x=\frac{-33}{15}:-\frac{23}{30}=\frac{-33}{15}\cdot-\frac{30}{23}=-\frac{66}{23}\)
mk k chắc nữa, tính nhẩm
bạn đúng đề:
\(\frac{x-5}{3}=\frac{y-4}{4}=\frac{z-3}{5}=\frac{x-5+y-4+z-3}{3+4+5}=\frac{36}{12}=3\)
\(\frac{x-5}{3}=3=\frac{x}{3}=3=9\Rightarrow x-5=9=14\Rightarrow x=14\)
\(\frac{y-4}{4}=3=\frac{y}{4}=3=12\Rightarrow y-4=12\Rightarrow16\)=> y=16
\(\frac{z-3}{5}=3=\frac{z}{5}=3=15\Rightarrow z-3=15=18\Rightarrow z=18\)
ta có \(1+\frac{x+5}{1995}+1+\frac{x+4}{1996}+1+\frac{x+3}{1997}=1+\frac{x+1995}{5}+1+\frac{x+1996}{4}+1+\frac{x+1997}{3}\)
\(=\frac{x+2000}{1995}+\frac{x+2000}{1996}+\frac{x+2000}{1997}=\frac{x+2000}{5}+\frac{x+2000}{4}+\frac{x+2000}{3}\)
\(=\left(x+2000\right)\left(\frac{1}{1995}+\frac{1}{1996}+\frac{1}{1997}\right)=\left(x+2000\right)\left(\frac{1}{5}+\frac{1}{4}+\frac{1}{3}\right)\) (1)
Xét \(\frac{1}{1995}+\frac{1}{1996}+\frac{1}{1997}\ne\frac{1}{5}+\frac{1}{4}+\frac{1}{3}vàx+2000=x+2000\) (2)
từ \(\left(1\right)\Leftrightarrow x+2000=0\) ( để (1) là đúng )
\(\Rightarrow x=2000\)
a.4^7
b.8^5
c.cho x mk sẻ tính kết quả nhưng tìm xmk ko tính đâu
\(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)+\frac{x+329}{5}=0\)
\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
(x + 329) . (1/327 + 1/326 + 1/325 + 1/324 + 1/5) = 0
1/327 + 1/326 + 1/325 + 1/324 + 1/5 khác 0
< = > x + 329 = 0
x= -329
\(\left|\frac{5}{4}x-\frac{7}{2}\right|=\left|\frac{5}{8}x+\frac{3}{5}\right|\)
\(\frac{5}{4}x-\frac{7}{2}=\frac{5}{8}x+\frac{3}{5}hay\frac{5}{4}x-\frac{7}{2}=\frac{-5}{8}x-\frac{3}{5}\)
\(\frac{5}{4}x-\frac{5}{8}x=\frac{7}{2}+\frac{3}{5}hay\frac{5}{4}x+\frac{5}{8}x=\frac{7}{2}-\frac{3}{5}\)
\(\frac{5}{8}x=\frac{41}{10}hay\frac{15}{8}x=\frac{29}{10}\)
x=164/25 hay x=232/150
\(\Leftrightarrow x+150=980.\frac{4}{5}+\frac{4}{5}.\left(-1\right)\)
\(\Leftrightarrow x+150=\frac{4}{5}.\left[980+\left(-1\right)\right]\)
\(\Leftrightarrow x+150=\frac{4}{5}.979\)
\(\Leftrightarrow x+150=783,2\)
\(\Leftrightarrow x=633,2\)