\(m=\frac{42}{46}+\frac{250}{286}+\frac{-2121}{2323}+\frac{-125125}{143143}\)
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\(\frac{42}{46}+\frac{250}{186}+\frac{-2121}{2323}+\frac{-125125}{143143}\Leftrightarrow\frac{21}{23}+\frac{125}{93}+\frac{-21}{23}+\frac{-125}{143}\)
\(\Rightarrow\left(\frac{21}{23}+\frac{-21}{23}\right)+\left(\frac{125}{93}+\frac{-125}{143}\right)=\frac{17000}{3999}\)
\(\frac{4}{46}+\frac{250}{186}+\frac{-2121}{2323}+\frac{-125125}{143143}=\frac{2}{23}+\frac{125}{93}-\frac{21}{23}-\frac{125}{143}\)
\(=-0,36\)
Nhơ nha bạn.Tích mình mình tích lại
a: =-11/23(6/7+8/7)-1/23
=-22/23-1/23
=-1
b: =21/23-21/23+125/143-125/143
=0
a) \(\frac{4}{20}+\frac{16}{42}+\frac{6}{15}+\frac{-3}{5}+\frac{2}{21}+\frac{-10}{21}+\frac{3}{20}\)
\(=\frac{1}{5}+\frac{8}{21}+\frac{2}{5}+\frac{-3}{5}+\frac{2}{21}+\frac{-10}{21}+\frac{3}{20}\)
= \(\left(\frac{1}{5}+\frac{2}{5}+\frac{-3}{5}\right)+\left(\frac{8}{21}+\frac{2}{21}+\frac{-10}{21}\right)+\frac{3}{20}\)
\(=\frac{0}{5}+\frac{0}{21}+\frac{3}{20}\)
\(=0+0+\frac{3}{20}\)
\(=\frac{3}{20}\)
b) \(\frac{42}{46}+\frac{250}{186}+\frac{-2121}{2323}+\frac{-125125}{143143}\)
\(=\frac{21}{23}+\frac{125}{93}+\frac{-21}{23}+\frac{-125}{143}\)
\(=\left(\frac{21}{23}+\frac{-21}{23}\right)+\frac{125}{93}+\frac{-125}{143}\)
\(=0+\frac{125}{93}+\frac{-125}{143}\)
\(=\frac{17875}{13299}+\frac{-11625}{13299}\)
\(=\frac{6250}{13299}\)
(Hình như câu b hơi sai)
\(a)\frac{4}{20}+\frac{16}{42}+\frac{6}{15}+\frac{-3}{5}+\frac{2}{21}+\frac{10}{21}+\frac{3}{20}\)
\(=\frac{1}{5}+\frac{8}{21}+\frac{2}{5}+\frac{-3}{5}+\frac{2}{21}+\frac{-10}{21}+\frac{3}{20}\)
\(=\left(\frac{1}{5}+\frac{2}{5}+\frac{-3}{5}\right)+\left(\frac{8}{21}+\frac{2}{21}+\frac{-10}{21}\right)+\frac{3}{20}\)
\(=0+0+\frac{3}{20}\)
\(=\frac{3}{20}\)
\(\frac{42}{44}+\frac{250}{286}+\frac{-2121}{2323}+\frac{-125125}{143143}\)
\(=\frac{21}{22}+\frac{125}{143}+\frac{-21}{23}+\frac{-125}{143}\)
\(=\left(\frac{21}{22}+\frac{-21}{23}\right)+\left(\frac{125}{143}+\frac{-125}{143}\right)\)
\(=\frac{483}{506}+\frac{-462}{506}+0\)
\(=\frac{21}{506}\)
Cbht