3.1/3x+16.3/4=-13.25 tìm x nha mn
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
`13,25xx2+13,25xx4+13,25xx2xx8`
`=13,25xxx(2+4+16)`
`=13,25xx22`
`=291,5`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1,\left(3x+2\right)\left(5-x^2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x+2=0\\5-x^2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{2}{3}\\-x^2=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{2}{3}\\x=\pm\sqrt{5}\end{matrix}\right.\)
Vậy \(S=\left\{-\dfrac{2}{3};-\sqrt{5};\sqrt{5}\right\}\)
\(2,-2x-\dfrac{2}{3}\left(\dfrac{3}{4}-\dfrac{1}{8}x\right)=\left(-\dfrac{1}{2}\right)^3\)
\(\Leftrightarrow-2x-\dfrac{1}{2}+\dfrac{1}{12}x=-\dfrac{1}{8}\)
\(\Leftrightarrow-2x+\dfrac{1}{12}x=-\dfrac{1}{8}+\dfrac{1}{2}\)
\(\Leftrightarrow-\dfrac{23}{12}=\dfrac{3}{8}\)
\(\Leftrightarrow x=-\dfrac{9}{46}\)
Vậy \(S=\left\{-\dfrac{9}{46}\right\}\)
\(3,\dfrac{1}{12}:\dfrac{4}{21}=3\dfrac{1}{2}:\left(3x-2\right)\)
\(\Leftrightarrow\dfrac{1}{12}.\dfrac{21}{4}=\dfrac{7}{2}.\dfrac{1}{3x-2}\)
\(\Leftrightarrow\dfrac{7}{16}=\dfrac{7}{6x-4}\)
\(\Leftrightarrow6x-4=7:\dfrac{7}{16}\)
\(\Leftrightarrow6x-4=16\)
\(\Leftrightarrow x=\dfrac{10}{3}\)
Vậy \(S=\left\{\dfrac{10}{3}\right\}\)
\(4,\dfrac{x-1}{x+2}=\dfrac{4}{5}\left(dk:x\ne-2\right)\)
\(\Rightarrow5\left(x-1\right)=4\left(x+2\right)\)
\(\Rightarrow5x-5=4x+8\)
\(\Rightarrow x=13\left(tmdk\right)\)
Vậy \(S=\left\{13\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
<=> x : ( 1/2+1/4+1/8) x 100 = 13.25
<=> x : ( 4/8 + 2/8 + 1/8) = 13.25 : 100
<=> x : 7/8 = 0,1325
<=> x = 0,1325 x 7/8
<=> x= 0.1159375
Chả biết đúng không nữa nhưng hình như là sai ế :)
x:1/2+x:1/4+x:25/2=13,25
x:(1/2+1/4+25/2)=13,25
x:53/4=13,25
x:53/4=53/4
x=53/4x53/4
x=2809/16
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow12x^2-42x-\left(8x-28\right)+\left(3x-12x^2\right)-\left(5-20x\right)=-31\)
\(\Leftrightarrow12x^2-42x-8x+28+3x-12x^2-5+20x=-31\)
\(\Leftrightarrow\left(12x^2-12x^2\right)-x\left(42+8\right)+x\left(3+20\right)+28-5=-31\)
\(\Leftrightarrow0-50x+23x+23=-31\)
\(\Leftrightarrow-27x=-31-23\)
\(\Leftrightarrow-27x=-54\)
\(\Leftrightarrow x=\left(-54\right)\div\left(-27\right)\)
\(\Leftrightarrow x=2\)
Vậy x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
2:
=>x^3-1-2x^3-4x^6+4x^6+4x=6
=>-x^3+4x-7=0
=>x=-2,59
4: =>8x-24x^2+2-6x+24x^2-60x-4x+10=-50
=>-62x+12=-50
=>x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
13.25 x0.5 + 13.25 x 0.25 + 13.25 x 0.125
= 13,25 x ( 0,5 + 0,25 + 0,125 )
= 13,25 x 0,875
= 11,59375
![](https://rs.olm.vn/images/avt/0.png?1311)
(2x+5):4-(32+16.3:6-15)=0
(2x+5):4-25=0
(2x+5):4 =0+25
(2x+5):4 =25
(2x+5) =25:4
2x+5 =6,25
2x =6,25-5
2x =1,25
x =1,25:2
x =0,625
các bạn nhớ k cho mình nha
(2x + 5 ): 4 - ( 32 + 16.3 : 6 - 15 ) = 0
(2x + 5 ) : 4 - ( 32 + 48 : 6 - 15 ) = 0
(2x + 5 ) : 4 - ( 32 + 8 - 15 ) = 0
(2x + 5) : 4 - 25 = 0
(2x + 5) : 4 = 0 + 25
(2x + 5 ) : 4 = 25
2x + 5 = 25 x 4
2x + 5 = 100
2x = 100 - 5
2x = 95
=> x = 95 : 2 = 47,5
![](https://rs.olm.vn/images/avt/0.png?1311)
a) |x| + |x-2| = 2
TH1: \(x< 0\Rightarrow-x-x+2=2\Leftrightarrow-2x=0\Rightarrow x=0\)
TH2: \(0\le x< 2\Rightarrow x-x+2=0\Rightarrow0x=-2\)(PT vô nghiệm)
TH3: \(x>2\Rightarrow x+x-2=0\Rightarrow2x=2\Rightarrow x=1\)(loại vì 1<2 không thỏa mãn ĐK)
b) |x-1| + |x-4| = 3x
TH1: \(x-1\le0\Rightarrow x\le1\)
\(-x+1-x+4=3x\Leftrightarrow5-2x=3x\Leftrightarrow5x=5\Rightarrow x=1\)
TH2: \(1\le x\le4\)
\(x-1-x+4=3x\Leftrightarrow3x=3\Rightarrow x=1\)
TH3: \(x\ge4\)
\(x-1+x-4=3x\Leftrightarrow2x-5=3x\Rightarrow x=-5\)(loại vì -5<4 không thỏa mãn với ĐK)
thank anh
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