tính bằng cách hợp lí :1/2+1/4+1/8+1/16
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=\(\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\)
=\(\frac{15}{16}\)
k mk nhé bạn
a)
Vì 2/9=6/27=8/36=12/54=16/72=18/81 nên:
2/9+6/27+8/36+12/54+16/72+18/81=
2/9+2/9+2/9+2/9+2/9+2/9=
2/9*6=
12/9=
4/3
Vậy 2/9+6/27+8/36+12/54+16/72+18/81=4/3
b)
Ta có:
1-2/5=3/5
1-2/7=5/7
1-2/9=7/9
...
1-2/99=97/99
Vậy (1-2/5)*(1-2/7)*(1-2/9)*...*(1-2/99)=
3/5*5/7*7/9*...*97/99=
(3*5*7*...*97)/(5*7*9*...*99)=
3/99=
1/33
Vậy (1-2/5)*(1-2/7)*(1-2/9)*...*(1-2/99)=1/33
c)
Gọi biểu thức 1/2+1/4+1/8+1/16+...+1/1024 là S,ta có:
S=1/2+1/4+1/8+1/16+...+1/1024
S*2=1+1/2+1/4+1/8+...+1/512
S*2-S=(1+1/2+1/4+1/8+...+1/512)-(1/2+1/4+1/8+1/16+...+1/1024)
S=1-1/1024
S=1023/1024
Vậy 1/2+1/4+1/8+1/16+...+1/1024=1023/1024
s=1/21 + 1/22+1/23+.........+1/210
2s= 1/22 +1/23+.........+1/210+1/211
2s-s= ( 1/22 +1/23+.........+1/210+1/211 ) -(1/21 + 1/22+1/23+.........+1/210)
s= 1/211 -1/2
\(0,25+25\%\times55+\dfrac{1}{4}\times45-\dfrac{2}{8}\)
\(=\dfrac{1}{4}+\dfrac{1}{4}\times55+\dfrac{1}{4}\times45-\dfrac{1}{4}\)
\(=\dfrac{1}{4}\times\left(1+55+45-1\right)\)
\(=\dfrac{1}{4}\times100\)
\(=25\)
\(0,25+25\%\times55+\dfrac{1}{4}\times45-\dfrac{2}{8}\)
\(=\dfrac{1}{4}+\dfrac{1}{4}\times55+\dfrac{1}{4}\times45-\dfrac{1}{4}\)
\(=\dfrac{1}{4}\times1+\dfrac{1}{4}\times55+\dfrac{1}{4}\times45-\dfrac{1}{4}\times1\)
\(=\dfrac{1}{4}+\left(1+55+45-1\right)\)
\(=\dfrac{1}{4}\times100\)
\(=0,25\times100\)
\(=25\)
\(#:)\)
Gọi biểu thức trên là A, ta có:
A = \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
A x 2 - A = \(\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)-\frac{1}{2}-\frac{1}{4}-\frac{1}{8}-\frac{1}{16}\)
A x 2 - A = A x 1 = A = \(1-\frac{1}{16}=\frac{15}{16}\)