3+3=
6-3=
1+2=
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Lời giải chi tiết:
6 – 3 – 1 = 2 | 1 + 3 + 2 = 6 | 6 – 1 – 2 = 3 |
6 – 3 – 2 = 1 | 3 + 1 + 2 = 6 | 6 – 1 – 3 = 2 |
6 – 3 – 1 = 2… | 1 + 3 + 2 = 6… | 6 – 1 – 2 = 3… |
6 – 3 – 2 = 1… | 3 + 1 + 2 = 6… | 6 – 1 – 3 = 2… |
1 + 3 + 2 = 6 6 - 3 -1 = 2 6 - 1 - 2 = 3
3 + 1 + 2 = 6 6 - 3 -2 = 1 6 - 1 - 3 = 2
1 + 3 + 2 =6 6 - 3 -1 =2 6 - 1 - 2 =3
3 + 1 + 2 = 6 6 - 3 -2 = 1 6 - 1 - 3 =2
5: \(=3-\dfrac{1}{4}+\dfrac{2}{3}-5+\dfrac{1}{3}+\dfrac{6}{5}-6+\dfrac{7}{4}-\dfrac{3}{2}\)
\(=3-5-6+\dfrac{-1}{4}+\dfrac{7}{4}+\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{6}{5}-\dfrac{3}{2}\)
\(=-8+\dfrac{3}{2}+1+\dfrac{-3}{10}\)
\(=-7+\dfrac{15-3}{10}=-7+\dfrac{6}{5}=-\dfrac{29}{5}\)
6: \(=6-\dfrac{2}{3}+\dfrac{1}{2}-5-\dfrac{5}{3}+\dfrac{3}{2}-3+\dfrac{7}{3}-\dfrac{5}{2}\)
\(=6-5-3-\dfrac{2}{3}-\dfrac{5}{3}+\dfrac{7}{3}+\dfrac{1}{2}+\dfrac{3}{2}-\dfrac{5}{2}\)
\(=-2-\dfrac{1}{2}=-\dfrac{5}{2}\)
7: \(=\dfrac{5}{3}-\dfrac{3}{7}+9-2-\dfrac{5}{7}+\dfrac{2}{3}+\dfrac{8}{7}-\dfrac{4}{3}-10\)
\(=9-2-10+\dfrac{5}{3}+\dfrac{2}{3}-\dfrac{4}{3}+\dfrac{-3}{7}-\dfrac{5}{7}+\dfrac{8}{7}\)
=-3+1
=-2
8: \(=8-\dfrac{9}{4}+\dfrac{2}{7}+6+\dfrac{3}{7}-\dfrac{5}{4}-3-\dfrac{2}{4}+\dfrac{9}{7}\)
\(=8+6-3+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{9}{7}-1-\dfrac{2}{4}\)
\(=11+2-1-\dfrac{1}{2}\)
=11+1/2
=11,5
Lời giải chi tiết:
5 + 1 = 6 | 4 + 2 = 6 | 3 + 3 = 6 |
1 + 5 = 6 | 2 + 4 = 6 | 3 + 3 = 6 |
6 – 5 = 1 | 6 – 2 = 4 | 6 – 3 = 3 |
6 – 1 = 5 | 6 – 4 = 2 | 6 - 3 = 3 |
1: =1/8*9/4=9/32
2: =8/27*243/32=9/4
3: =(5/4*4/5)^5*(4/5)^2=16/25
4: \(=\left(-\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^2\cdot\left(\dfrac{6}{5}\right)^2=\dfrac{36}{25}\)
5: \(=\left(-\dfrac{4}{3}\right)^3\cdot\left(\dfrac{3}{4}\right)^{10}=\left(-1\right)\left(\dfrac{3}{4}\right)^7=-\left(\dfrac{3}{4}\right)^7\)
6: \(=\left(\dfrac{1}{3}\cdot\dfrac{-9}{2}\right)^4\left(-\dfrac{9}{2}\right)^2=\left(-\dfrac{3}{2}\right)^4\cdot\dfrac{81}{4}=\dfrac{9}{4}\cdot\dfrac{81}{4}=\dfrac{729}{16}\)
8: =(0,2*5)^4*5^2=25
10: =-0,5^5*2^10
=-0,5^5*2^5*2^5
=-32
13: =(0,5*2)^2*2^2=4
= 6
= 3
= 3
3 + 3 = 6
6-3 = 3
1+2 =4