Tìm x biết:
a) x – 345 094 = 123 357
b) x : 13 = 125
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123+x+2x=2x+345-236
<=>x+2x-2x=345-236-123
<=>x=-14
vậy x=-14
1324+x+x=125-2x-3x
<=>x+x-2x-3x=125-1324
<=>-3x=-1199
<=>x=\(\frac{1999}{3}\)
vậy x=\(\frac{1999}{3}\)
k mk nha mấy bạn
a) x – 123 = 345 b) x + 254 = 665
x = 345 + 123 x = 665 – 254
x = 468 x = 211
a) \(5\times x-123=12\)
\(\Rightarrow5\times x=135\)
\(\Rightarrow x=27\)
b) \(x+3x+5x+7x=96\)
\(\Rightarrow16x=96\)
\(\Rightarrow x=6\)
a) \(5\times x-123=12\)
\(5x=12+123\)
\(5x=135\)
\(x=135:5\)
\(x=27\)
________
b) \(x+3x+5x+7x=96\)
\(x\left(1+3+5+7\right)=96\)
\(x.16=96\)
\(x=96:16\)
\(x=6\)
a: =>4(x-3)=49-1=48
=>x-3=12
=>x=15
b: =>123-5(x+4)=38
=>5(x+4)=123-38=85
=>x+4=17
=>x=13
c: =>2x-138=9*8=72
=>2x=72+138=210
=>x=105
a) \(\left(5-x\right)\left(x-1\right)=-2x\left(x-1\right)\)
\(\Rightarrow\left(5-x\right)\left(x-1\right)+2x\left(x-1\right)=0\)
\(\Rightarrow\left(x-1\right)\left(5-x+2x\right)=0\)
\(\Rightarrow\left(x-1\right)\left(x+5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=1\\x=-5\end{matrix}\right.\)
b) \(\left(x+3\right)^2-\left(x-13\right)\left(x+13\right)=0\)
\(\Rightarrow x^2+6x+9-x^2+169=0\)
\(\Rightarrow6x=-178\Rightarrow x=-\dfrac{89}{3}\)
\(123-\left(x+345\right)-2x=1792\)
\(\Leftrightarrow123-x-345-2x=1792\)
\(\Rightarrow-222-3x=1792\)
\(\Leftrightarrow-3x=1792+\left(-222\right)\)
\(\Leftrightarrow-3x=1570\)
\(\Rightarrow x=\frac{-1570}{3}\)
123 – (x + 345) – 2x = 1792
123 – x – 345 – 2x = 1792
–222 – 3x = 1792
–3x = 1792 + 222
–3x = 2014
=> x = – 2014/3
a) x – 345 094 = 123 357
x = 123 357 + 345 094
x = 468 451
b) x : 13 = 125
x = 125 x 13
x = 1625
a: =>x=123357+345094=468451
b: =>x=125x13=1625