giúp mình với
A=
3+3.3+3.3.3+.....+3.3.3.3.3.3{20lan}
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1+3+3.3+3.3.3+3.3.3.3+3.3.3.3.3
=1+3+32+33+34+35
=(1+3+32) + ( 33+34+35 )
= 13 + 33 + (1+32+33)
=13 + 33 + 13
=13.(1+33) chia hết cho 13
a) \(x^4+x^3-8x-8\)
\(=x^3\left(x+1\right)-8\left(x+1\right)\)
\(=\left(x^3+8\right)\left(x+1\right)\)
\(=\left(x+2\right)\left(x^2-2x+4\right)\left(x+1\right)\)
a) \(=x^3\left(x+1\right)-8\left(x+1\right)=\left(x+1\right)\left(x^3-8\right)=\left(x+1\right)\left(x-2\right)\left(x^2+2x+4\right)\)
b) \(=y\left(x+2\right)-3\left(x+2\right)=\left(x+2\right)\left(y-3\right)\)
c) \(=3\left(x-y\right)-a\left(x-y\right)=\left(x-y\right)\left(3-a\right)\)
\(S=C_n^1.3+C_n^2.3^2+.....+C_n^n.3^n\)
\(S=C_n^0.3^0+C_n^1.3^1+C_n^2.3^2+.....+C_n^n.3^n-1\)
\(S=\left(1+3\right)^n-1=4^n-1\)
a)\(x^4+3x^3+x^2+3x=x\left(x^3+3x^2+x+3\right)\)
\(=x\left[x^2\left(x+3\right)+\left(x+3\right)\right]=x\left(x+3\right)\left(x^2+1\right)\)
b) \(x^2+6xy+9y^2-4z^2=\left(x+3y\right)^2-4z^2=\left(x+3y-2z\right)\left(x+3y+2z\right)\)
c) \(=2x\left(x-1\right)-7\left(x-1\right)=\left(x-1\right)\left(2x-7\right)\)
\(a,=x^3\left(x+3\right)+x\left(x+3\right)=x\left(x^2+1\right)\left(x+3\right)\\ b,=\left(x+3y\right)^2-4z^2=\left(x+3y+2z\right)\left(x+3y-2z\right)\\ c,=2x^2-2x-7x+7=\left(x-1\right)\left(2x-7\right)\)
Ta có: \(A=\dfrac{1-0.5\cdot\left(3.84-2.4\right):0.8}{\dfrac{4}{5}-\left(1\dfrac{1}{3}-2\dfrac{1}{6}\right)-1.5}\)
\(=\dfrac{1-0.5\cdot1.44:0.8}{\dfrac{4}{5}-\left(\dfrac{4}{3}-\dfrac{13}{6}\right)-\dfrac{3}{2}}\)
\(=\dfrac{1-0.9}{\dfrac{4}{5}+\dfrac{5}{6}-\dfrac{3}{2}}=\dfrac{0.1}{\dfrac{2}{15}}=\dfrac{3}{4}\)
Giải:
A=1-0,5.(3,84-2,4):0,8 / 4/5-(1 1/3 - 2 1/6)-1,5
A=1-0,5.1,44:0.8 / 4/5-(4/3-13/6)-3/2
A=1-0.9 / 4/5-(-5/6)-3/2
A=0.1 / 2/15
A= 1/10 : 2/15
A=3/4
Chúc bạn học tốt!
nó là bang 20
kết quả này
3*20=60 nghe bạn