- 2/3:3/4x3=
- 1/8:5/6:1/3=
- 2/5:6/5x2/3=
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DM
1
3 tháng 8 2018
\(a,\frac{2}{5}:\frac{6}{5}+\frac{3}{4}.\frac{12}{5}\)
=\(\frac{2}{5}.\frac{5}{6}+\frac{9}{5}\)
=\(\frac{1}{3}+\frac{9}{5}\)
=\(\frac{32}{5}\)
b) \(\frac{17}{5}.\frac{3}{5}.\frac{17}{5}.\frac{2}{5}\)
=\(\frac{17}{5}.\left(\frac{3}{5}.\frac{2}{5}\right)\)
=\(\frac{17}{5}.\frac{6}{25}\)
=\(\frac{102}{125}\)
c)\(\frac{1}{4}+\frac{3}{4}.\frac{2}{3}-\frac{1}{2}\)
=\(\frac{1}{4}+\frac{1}{2}-\frac{1}{2}\)
=\(\frac{1}{4}\)
d)\(\frac{6}{7}+\frac{5}{8}:5\)
=\(\frac{6}{7}+\frac{5}{8}.\frac{1}{5}\)
=\(\frac{6}{7}+\frac{1}{8}\)
=\(\frac{48}{56}+\frac{7}{56}\)
=\(\frac{55}{56}\)
tk nhé bn!
3 tháng 6 2023
1: Sửa đề: 3x-5
\(=\dfrac{-x^2\left(3x-5\right)-3\left(3x-5\right)}{3x-5}=-x^2-3\)
2: \(=\dfrac{5x^4-5x^3+14x^3-14x^2+12x^2-12x+8x-8}{x-1}\)
=5x^2+14x^2+12x+8
3: \(=\dfrac{5x^3+10x^2+4x^2+8x+4x+8}{x+2}=5x^2+4x+4\)
4: \(=\dfrac{\left(x^2-1\right)\left(x^2+1\right)-2x\left(x^2-1\right)}{x^2-1}=x^2+1-2x\)
5: \(=\dfrac{x^2\left(5-3x\right)+3\left(5-3x\right)}{5-3x}=x^2+3\)
6 tháng 6 2017
1) \(x^2-7x+6=x^3+1-7x-7=\left(x^3+1\right)-7\left(x+1\right)=\left(x+1\right)\left(x^2-x-6\right)\)
2) \(x^3-9x^2+6x+16\)
\(\left(x^3+1\right)-\left[\left(9x^2-6x+1\right)-16\right]\)
\(=\left(x^3+1\right)-\left[\left(3x-1\right)^2-16\right]=\left(x^3+1\right)-\left(3x-1+4\right)\left(3x-1-4\right)\)\(=\left(x^3+1\right)-3\left(3x-5\right)\left(x+1\right)\)\(=\left(x+1\right)\left[x^2-x+1-9x+15\right]=\left(x+1\right)\left(x^2-10x+16\right)\)
\(=\left(x+1\right)\left[x\left(x-2\right)-8\left(x-2\right)\right]\)\(\left(x+1\right)\left(x-2\right)\left(x-8\right)\)
3) \(x^3-6x^2-x+30\)
\(=x^3-5x^2-x^2+5x-6x+30\)
\(=x^2\left(x-5\right)-x\left(x-5\right)-6\left(x-5\right)\)
\(=\left(x-5\right)\left(x^2-x-1\right)\)
4) \(2x^3-x^2+5x+3=\left(2x^3+x^2\right)-\left(2x^2+x\right)+\left(6x+3\right)\)
\(=x^2\left(2x+1\right)-x\left(2x+1\right)+3\left(2x+1\right)\)
\(=\left(2x+1\right)\left(x^2-x+3\right)\)
5) \(27x^3-27x^2+18x-4=\left(27x^3-1\right)-\left(27x^2-18x+3\right)\)
\(=\left(3x-1\right)\left(9x^2+3x+1\right)-3\left(9x^2-6x+1\right)\)
\(=\left(3x-1\right)\left(9x^2+3x+1\right)-3\left(3x-1\right)^2\)
\(=\left(3x-1\right)\left(9x^2+3x+1-9x+3\right)=\left(3x-1\right)\left(9x^2-6x+4\right)\)
gửi phần này trước còn lại làm sau !!! tk mk nka !!!
CM
9 tháng 6 2018
Chọn B
Ta có A(x) + B(x) = (3x4 - 4x3+ 5x2 - 3-4x) + (-3x4+ 4x3 - 5x2+ 6 + 2x) = -2x + 3.
7 tháng 12 2020
Ta có :
\(3x^4-4x^3+5x^2-3-4x-3x^4+4x^3-5x^2+6+2x\)
\(=3-2x\)hay \(-2x+3\)
Suy ra : Ta chọn B
22 tháng 2 2016
= 5/3 - (8x-1)/3 = (4x + 2)/5 - 25/5
=> (5-8x+1)/3 = (4x + 2 - 25)/5
=> (6-8x)*5 = (4x-23)*3
=> 30 - 40x = 12 x - 69
=> 52x = 99
x = 90/52
1= 2/3:3/4*3=8/3
2=1/8:5/6:1/3=9/20
3=2/5:6/5*2/3=2/9
Chúc bạn học tốt!