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DT
Đỗ Thanh Hải
CTVVIP
4 tháng 9 2021
1 saw- would be
2 found - would take
3 would be - told
4 stay - won't see
5 will learn - have
6 will be - don't go
7 gives - will feel
8 wouldn't go - rained
9 would solve - knew
10 would you do - had
4 tháng 9 2021
1. saw- would be
2. found - would take
3. would be - told
4. stay - won't see
5. will learn - have
6. will be - don't go
7. gives - will feel
8. wouldn't go - rained
9. would solve - knew
10. would you do - had
NV
Nguyễn Việt Lâm
Giáo viên
10 tháng 5 2021
\(y'=3x^2-6x\)
a.
Ta có: \(y'\left(2\right)=3.2^2-6.2=0\)
Tiếp tuyến tại M có dạng:
\(y=0\left(x-2\right)-2\Leftrightarrow y=-2\)
b.
Tiếp tuyến song song với \(y=-3x+2014\) nên có hệ số góc k thỏa mãn \(k=-3\)
Gọi hoành độ tiếp điểm là \(x_0\Rightarrow y'\left(x_0\right)=-3\)
\(\Rightarrow3x^2_0-6x_0=-3\Leftrightarrow3\left(x_0-1\right)^2=0\Rightarrow x_0=1\)
\(\Rightarrow y_0=0\)
Phương trình tiếp tuyến:
\(y=-3\left(x-1\right)+0\Leftrightarrow y=-3x+3\)
c.
Tiếp tuyến vuông góc với \(y=-\dfrac{1}{3}x+2013\) nên có hệ số góc thỏa mãn:
\(k\left(-\dfrac{1}{3}\right)=-1\Rightarrow k=3\)
Gọi hoành độ tiếp điểm là \(x_0\Rightarrow y'\left(x_0\right)=3\)
\(\Rightarrow3x^2_0-6x_0=3\Rightarrow\left[{}\begin{matrix}x_0=1+\sqrt{2}\Rightarrow y_0=-\sqrt{2}\\x_0=1-\sqrt{2}\Rightarrow y_0=\sqrt{2}\end{matrix}\right.\)
Có 2 tiếp tuyến thỏa mãn: \(\left[{}\begin{matrix}y=3\left(x-1-\sqrt{2}\right)-\sqrt{2}\\y=3\left(x-1+\sqrt{2}\right)+\sqrt{2}\end{matrix}\right.\)
Giúp mik với mn ưi
NB
5 tháng 7 2023
1. Have read
2. Was doing - sent - had given
3. Was doing
4. Will be living
5. Will be working
6. Finish
7. Looked - was trying
8. Were - had started - got
9. Have worked
10. Have ever met
11. Came - had stood
12. Had buzzed - answered
13. Had - was repairing
14. Saw - was sitting - told - had been reading
15. Was weeding - was cutting
16. Will be waiting
\(\dfrac{-3}{80}.\dfrac{-2}{3}=\dfrac{1}{40}\)