Tìm x.
19\20-x bằng 8\5-3\4 bằn
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)
x + 2/5 = 1/2
x = 1/2 - 2/5
x = 1/10
b)
x + 3/7 = 2/5 + 3/10
x + 3/7 = 7/10
x = 7/10 - 3/7
x = 19/70
c)
19/20 - x = 8/5 - 3/4
19/20 - x = 17/20
x = 19/20 - 17/20
x = 1/5
a) x + 2/5 = 1/2
x = 1/2 - 2/5
x = 3/10
b) x + 3/7 = 2/5 + 3/10
x + 3/7 = 7/10
x = 7/10 - 3/7
x = 19/70
c) 19/20 - x = 8/5 - 3/4
19/20 - x = 17/20
x = 19/20 - 17/20
x = 2/20 = 1/10
a/ 25x+1.1252=6254
<=> (52)x+1.(53)2=(54)4
<=> 52x+2.56 = 516
<=> 52x+2=510
=> 2x+2=10 => x=4
b/ 9x=273.35
<=> 32x=39.35=314
=> 2x=14 => x=7
c/ 16x.85=647
<=> (24)x.(23)5=(26)7
<=> 24x.215=242
<=> 24x=227
=> 4x=27 => x=27/4
\(\frac{19}{20}-x+\frac{3}{4}=\frac{8}{5}\)
\(\frac{19}{20}-x=\frac{8}{5}-\frac{3}{4}\)
\(\frac{19}{20}-x=\frac{17}{20}\)
\(x=\frac{19}{20}-\frac{17}{20}\)
\(x=\frac{1}{10}\)
\(\frac{19}{20}-x+\frac{3}{4}=\frac{8}{5}\)
\(1,7-x=1,6\)
\(x=1,7-1,6\)
\(x=0,1\)
a/\(\dfrac{19}{20}-y=\dfrac{8}{5}-\dfrac{3}{4}\)
\(\dfrac{19}{20}-y=\dfrac{17}{20}\)
\(y=\dfrac{19}{20}-\dfrac{17}{20}\)
\(y=\dfrac{2}{20}=\dfrac{1}{10}\)
b/\(y:\dfrac{2}{3}=\dfrac{4}{9}\times3\)
\(y:\dfrac{2}{3}=\dfrac{4}{3}\)
\(y=\dfrac{4}{3}\times\dfrac{2}{3}\)
\(y=\dfrac{8}{9}\)
#データネ
a) 19/20 - y = 8/5 - 3/4
19/20 - y = 17/20
y = 17/20 + 19/20
y = 36/20
b) y : 2/3 = 4/9 x 3
y : 2/3 = 12/9
y = 12/9 x 2/3
y = 24/27
tích cho mik nhaaaaaaaaaaa
3:
\(=\dfrac{1}{7}\cdot\dfrac{3}{5}\cdot\dfrac{5}{6}\cdot\dfrac{5}{8}=\dfrac{1}{7}\cdot\dfrac{1}{2}\cdot\dfrac{5}{8}=\dfrac{5}{112}\)
4:
=>2/3:x=-2-1/3=-7/3
=>x=-2/3:7/3=-2/7
5:
AC=CB=12/2=6cm
IB=6/2=3cm
\(2x+3=8\)
\(\Rightarrow2x=8-3\)
\(\Rightarrow2x=5\)
\(\Rightarrow x=\dfrac{5}{2}\)
\(x:5-2=3\)
\(\Rightarrow x:5=3+2\)
\(\Rightarrow x:5=5\)
\(\Rightarrow x=5\cdot5\)
\(\Rightarrow x=25\)
\(x:7-2=19\)
\(\Rightarrow x:7=19+2\)
\(\Rightarrow x:7=21\)
\(\Rightarrow x=21\cdot7\)
\(\Rightarrow x=147\)
Mình chưa rõ đề
\(20-\left(x+3\right)=5\)
\(\Rightarrow-x-3=5-20\)
\(\Rightarrow-x-3=-15\)
\(\Rightarrow-x=-15+3\)
\(\Rightarrow-x=-12\)
\(\Rightarrow x=12\)