(16/15.31)+(14/31.45)+(7/45.52)+(7/52.65)+(1/13.70)
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\(\frac{16}{15.31}+\frac{14}{31.45}+\frac{7}{45.52}+\frac{13}{52.65}+\frac{1}{13.70}\)
\(=\frac{16}{15.31}+\frac{14}{31.45}+\frac{7}{45.52}+\frac{13}{52.65}+\frac{5}{65.70}\)
\(=\frac{1}{15}-\frac{1}{31}+\frac{1}{31}-\frac{1}{45}+\frac{1}{45}-\frac{1}{52}+\frac{1}{52}-\frac{1}{65}+\frac{1}{65}-\frac{1}{70}=\frac{1}{15}-\frac{1}{70}=\frac{11}{210}\)
. Tham khảo nha !!!
\(\frac{16}{15.31}+\frac{14}{31.45}+\frac{7}{45.52}+\frac{7}{52.65}+\frac{1}{13.70}\)
\(=\frac{16}{15.31}+\frac{14}{31.45}+\frac{7}{45.52}+\frac{7}{52.65}+\frac{5}{65.70}\)
\(=\frac{1}{15}-\frac{1}{31}+\frac{1}{31}-\frac{1}{45}+\frac{1}{45}-\frac{1}{52}+\frac{1}{52}-\frac{1}{65}+\frac{1}{65}-\frac{1}{70}\)
\(=\frac{1}{15}-\frac{1}{70}\)
\(=\frac{70}{1050}-\frac{15}{1050}\)
\(=\frac{55}{1050}\)
\(=\frac{11}{210}\)
Chúc bạn học tốt !!!
= 1/15 - 1/31 + 1/31 - 1/45 + 1/45 - 1/52 + 1/52 - 1/65 + 1/13.70
= 1/15 - 1/65 + 1/13.70
= 2/39 + 1/910
= 11/210
Tk mk nha
Lời giải:
$A=\frac{15-5}{5.15}+\frac{31-15}{15.31}+\frac{45-31}{31.45}+\frac{52-45}{45.52}+\frac{65-52}{52.65}+\frac{1}{13.70}+\frac{1}{70.15}$
$=\frac{1}{5}-\frac{1}{15}+\frac{1}{15}-\frac{1}{31}+\frac{1}{31}-\frac{1}{45}+\frac{1}{45}-\frac{1}{52}+\frac{1}{52}-\frac{1}{65}+\frac{1}{70}(\frac{1}{13}+\frac{1}{15})$
$=\frac{1}{5}-\frac{1}{65}+\frac{1}{70}.\frac{28}{195}$
$=\frac{12}{65}+\frac{2}{95}$
$=\frac{254}{1325}$
\(\dfrac{1}{4444}< 1,\dfrac{3}{7}< 1,\dfrac{9}{5}>1,\dfrac{7}{3}>1,\dfrac{14}{15}< 1,\dfrac{16}{16}=1,\dfrac{14}{11}>1\)
\(\frac{1}{4}< 1\) ; \(\frac{3}{7}< 1\) ; \(\frac{9}{5}>1\)
\(\frac{7}{3}>1\) ; \(\frac{14}{15}< 1\) ; \(\frac{16}{16}=1\) ; \(\frac{14}{11}>1\)
1/4 < 1; 3/7 < 1; 9/5 > 1; 14/15 < 1; 16/16 = 1; 14/11 > 1.
a, 4 . 24 . 5 2 - 3 3 . 18 + 3 3 . 12
= 100.24–27.30
= 2400 – 810
= 1590
b, 2 3 . 7 . 5 3 - 5 2 . 65 + 5 2 . 35
= 7.1000 – 25.100
= 7000 – 2500
= 4500
c, 2 2 . 74 . 5 2 + 5 2 . 26 . 4 - 7000
= 100.74 + 100.26 – 70.100
= 100.(74+26–70)
= 100.30
= 3000
d, 55 . 2 2 . 5 + 4 . 89 . 5 2 - 3 2 . 10 3
= 25.4.11 + 4.25.89 – 90.100
= 100.11 + 100.89 – 100.90
= 100.(11+89–90)
= 100.10
= 1000
e, [(315+372).3+(372+315).7]:(26.13+74.13+74)
= [687.3+687.7]:(13.(26+74)+74)
= (687.10):(13.100+74)
= 6870:1374
= 5