2+33
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\(\frac{33}{2}+\frac{33}{6}+\frac{33}{18}+\frac{33}{54}+\frac{33}{162}+\frac{33}{486}\)
\(=\frac{33.3+33.3+33.3+33.3+33.3}{486}\)
\(=\frac{99.5}{486}\)
\(=\frac{495}{486}\)
Gọi \(A=\frac{33}{2}+\frac{33}{6}+...+\frac{33}{486}\)
\(A=33.\left[\left(\frac{1}{1.2}+\frac{1}{2.3}\right)+\left(\frac{1}{3.6}+\frac{1}{6.9}\right)\left(\frac{1}{9.18}+\frac{1}{18.27}\right)\right]\)
\(A=33.\left[\frac{2}{3}+\frac{2}{9}+\frac{2}{27}\right]\)
\(A=66.\left[\frac{9}{27}+\frac{3}{27}+\frac{1}{27}\right]\)
\(A=66.\frac{13}{27}\)
\(A=\frac{286}{9}\)
sai hay đúng cx ko biết nha
Ta có:
2m−2n=5122m−2n=512
⇒2n.(2m−n−1)=512⇒2n.(2m−n−1)=512
2m−2n=5122m−2n=512
⇒2m>2n.⇒2m>2n.
⇒m>n⇒m>n
⇒2m−n−1⇒2m−n−1 là số lẻ.
⇒2m−n−1=1⇒2m−n−1=1
⇒2n.1=512⇒2n.1=512
⇒2n=512:1⇒2n=512:1
⇒2n=512⇒2n=512
⇒2n=29⇒2n=29
⇒n=9.⇒n=9.
⇒2m=512+512⇒2m=512+512
⇒2m=1024⇒2m=1024
⇒2m=210⇒2m=210
⇒m=10.⇒m=10.
Vậy m=10;n=9.
=> 2n(2m-n - 1)=512
2m - 2n = 512
=> 2m > 2n
=> m>n
Ta có 2m-n là 1 số luôn chẵn
=> 2m-n - 1 là 1 số luôn lẻ
Ta đặt 2m-n-1 =1
=> 2n(2m-n - 1)= 2n . 1 = 2n = 512 = 29
=> n=9
Ta thay n=9
=> 2m - 2n = 512
2m - 512= 512
2m = 512+512 =1024 = 210
=> m=10
Kết luận : m=10 ; n= 9
Học tốt nhé!
\(=2.\left[\left(7-1\right):22+99\right]-100\\ =2.\left(6:22+99\right)-100\\ =2.\left(\dfrac{3}{11}+99\right)-100\\ =2.\left(\dfrac{3}{11}+\dfrac{1089}{11}\right)-100\\ =2.\dfrac{1092}{11}-100\\ =\dfrac{2184}{11}-100\\ =\dfrac{1084}{11}\)
\(\left(\frac{2}{31\times33}+\frac{2}{33\times35}+...+\frac{2}{39\times41}\right)\times2542-2,04:x=19\)
\(\Rightarrow\left(\frac{1}{31}-\frac{1}{33}+\frac{1}{33}-\frac{1}{35}+...+\frac{1}{39}-\frac{1}{41}\right)\times2542-2,04:x=19\)
\(\Rightarrow\left(\frac{1}{31}-\frac{1}{41}\right)\times2542-2,04:x=19\)
\(\Rightarrow\frac{10}{1271}\times2542-2,04:x=19\)
\(\Rightarrow20-2,04:x=19\)
\(\Rightarrow2,04:x=20-19\)
\(\Rightarrow2,04:x=1\)
\(\Rightarrow x=2,04:1\)
\(\Rightarrow x=2,04\)
Vậy x = 2,04
\(\left(\frac{2}{31\text{ x }33}+\frac{2}{33\text{ x }35}+...+\frac{2}{39\text{ x }41}\right)\text{ x }2542-2,04\text{ : }x=19\)
\(\left(\frac{1}{31}-\frac{1}{33}+\frac{1}{33}-\frac{1}{35}+...+\frac{1}{39}-\frac{1}{41}\right)\text{ x }2542-2,04\text{ : }x=1\)
\(\left(\frac{1}{31}-\frac{1}{41}\right)\text{ x }2542-2,04\text{ : }x=1\)
\(\frac{10}{1271}\text{ x }2542-2,04\text{ : }x=1\)
\(20-2,04\text{ : }x=1\)
\(2,04\text{ : }x=20-1\)
\(2,04\text{ : }x=19\)
\(x=2,04\text{ : }19\)
\(x=\frac{51}{475}\)
\(=\dfrac{15}{17}\left(\dfrac{45}{33}-\dfrac{12}{33}\right)=\dfrac{15}{17}\)
2 + 33 = 35
35 nhé em
HT