Giúp mình đi ạ ko cần giúp hết đâu ạ Thanksss😿😿
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\(\lim\dfrac{3^n+2.6^n}{6^{n-1}+5.4^n}=\lim\dfrac{6^n\left[\left(\dfrac{3}{6}\right)^n+2\right]}{6^n\left[\dfrac{1}{6}+5\left(\dfrac{4}{6}\right)^n\right]}=\lim\dfrac{\left(\dfrac{3}{6}\right)^n+2}{\dfrac{1}{6}+5\left(\dfrac{4}{6}\right)^n}=\dfrac{0+2}{\dfrac{1}{6}+0}=12\)
\(\lim\left(\sqrt{n^2+9}-n\right)=\lim\dfrac{\left(\sqrt{n^2+9}-n\right)\left(\sqrt{n^2+9}+n\right)}{\sqrt{n^2+9}+n}=\lim\dfrac{9}{\sqrt{n^2+9}+n}\)
\(=\lim\dfrac{n\left(\dfrac{9}{n}\right)}{n\left(\sqrt{1+\dfrac{9}{n^2}}+1\right)}=\lim\dfrac{\dfrac{9}{n}}{\sqrt{1+\dfrac{9}{n^2}}+1}=\dfrac{0}{1+1}=0\)
\(\lim\dfrac{\sqrt{15+9n^2}-3}{5-n}=\lim\dfrac{n\sqrt{\dfrac{15}{n^2}+9}-3}{5-n}=\lim\dfrac{n\left(\sqrt{\dfrac{15}{n^2}+9}-\dfrac{3}{n}\right)}{n\left(\dfrac{5}{n}-1\right)}\)
\(=\lim\dfrac{\sqrt{\dfrac{15}{n^2}+9}-\dfrac{3}{n}}{\dfrac{5}{n}-1}=\dfrac{\sqrt{9}-0}{0-1}=-3\)
3.Have you finished your homework yet?
5.I have never donated blood before
tớ biết mỗi 2 câu này thôi
a: BC=căn 6^2+8^2=10cm
AM=BC/2=5cm
b:
ΔAEH vuông tại A có AI là trung tuyến
nên IH=IA
=>góc IHA=góc IAH
góc IAH+góc MAB
=góc MBA+góc IHA=90 độ
=>góc IAM=90 độ
=>AI vuông góc AM
2. It is thought that he stole the money.
He is thought to have stolen the money.
3. It is said that she is going to study abroad.
She is said to be going to study abroad.
4. It is thought that the house was broken into last night.
The house was thought to be broken into last night.
was thought that the house was broken into last night.
house was thought to have been broken into last night.
hotel regulations should be read carefully by the hotel guests.
languages are spoken in Canada?
bike was left in the hall this morning.