84:4+3 mũ 9:3 mũ 7+5 mũ 0
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a)-84:4+3^9:3^7+5^0
=-21+(3^9:3^7)+1
=-21+3^2+1
=-21+9+1
=-12+1
=-11
b)295-(31-2^5.5)^2
=295-(31-32.5)^2
=295-(-129)^2
=295+129^2
=295-16641
=-16346
tick cho mk nha bạn
a) -84 : 4 + 3^ 9 : 3 ^ 7 + 5 ^0
=-84:4+3^2+1
=-84:4+9+1
=-21+9+1
=-12+1
=-11
b) 295 - ( 31 - 2^ 5. 5) ^2
= 295 - ( 31 -32. 5)^2
= 295 - (-129)^2
=295-16641
=-16346
a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
a,3.52+(15.22-23.22)
= 156 + 22(15 - 23)
= 156 + 22. (-8)
= 156 - 176
= -20
b,75.34+76.75-75.10
= 75(34 + 76 - 10)
= 75. 100
= 7500
c,84:4+3 mũ 9 : 3 mũ 7 +2017 mũ 0
= 84 : 4 + 39 : 37 + 20170
= 21 + 9 + 1
= 31
a) Ta có: \(3\cdot52+\left(15\cdot22-23\cdot22\right)\)
\(=3\cdot52+22\cdot\left(15-23\right)\)
\(=3\cdot52+22\cdot\left(-8\right)\)
\(=156-176=-20\)
b) Ta có: \(75\cdot34+76\cdot75-75\cdot10\)
\(=75\cdot\left(34+76-10\right)\)
\(=75\cdot\left(110-10\right)\)
\(=75\cdot100\)
\(=7500\)
c) Ta có: \(84:4+3^9:3^7+2017^0\)
\(=21+3^{9-7}+1\)
\(=22+3^2\)
\(=22+9=31\)
84 : 4 + 39 : 37 + 5
= 21 + 39 - 7 + 5
= \(21 +3^{2} + 5\)
= \(21 +9 + 5\)
= 35
`#3107.101107`
\(3^9\div3^8+5^8\div5^7\\ =3^{9-8}+5^{8-7}\\ =3+5\\ =8\)
_______
\(6^9\div6^7-30\\ =6^{9-7}-30\\ =6^2-30\\ =36-30\\ =6\)
________
\(\left(2^7\times2^2\right)\div2^9-5^0\\ =2^{7+2}\div2^9-1\\ =2^9\div2^9-1\\ =2^0-1\\ =1-1\\ =0\)
_______
\(3\times3\times3\times3\times3\times3^5\\ =3^{1+1+1+1+1+5}\\ =3^{10}\)
Bài 1:
a) 02002 < 02023
b) 20220 = 20230
c) 549 < 5510
d) ( 4 + 5 )3 > 42 + 52
đ) 92 - 32 > ( 9 - 3 )2
Bài 2:
a) 32 x 43 - 32 + 333
= 9 x 64 - 9 + 333
= 576 - 9 + 333
= 567 + 333
= 900
b) 5 x 43 + 24 x 5 + 410
= 5 x 64 + 24 x 5 + 1
= 5 x ( 64 + 24 ) + 1
= 5 x 88 + 1
= 440 + 1
= 441
c) 23 x 42 + 32 x 5 - 40 x 12023
= 8 x 16 + 9 x 5 - 40 x 1
= 128 + 45 - 40
= 133
Bài 1 :
a) \(0^{2002}=0;0^{2023}=0\Rightarrow0^{2002}=0^{2023}\)
b) \(2022^0=1;2023^0=1\Rightarrow2022^0=2023^0\)
c) \(54^9< 55^9;55^9< 55^{10}\Rightarrow54^9< 55^{10}\)
d) \(\left(4+5\right)^3>\left(4+5\right)^2;\left(4+5\right)^2>4^2+5^2\Rightarrow\left(4+5\right)^3>4^2+5^2\)
đ) \(9^2-3^2=81-9=82;\left(9-3\right)^2=6^2=36\Rightarrow9^2-3^2>\left(9-3\right)^2\)
=21+9+1=31