A) 79-(79-2021)
b) 4mũ 5 : 4mũ 3 - 8
c) 17.(-85)+17.85
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A=1+3+3^2+3^3+3^4+...+3^100
3A=3+3^2+3^3+3^4+...+3^101
3A-A=(3+3^2+3^3+3^4+...+3^101)-(1+3+3^2+3^3+3^4+...+3^100)
2A=3^101-1
A=(3^101-1):2
phần b làm tương tự phần a nhưng mà là nhân cả biểu thức B với 4 nhé
a)
70 - 5 . ( x -3 ) = 45
5 . ( x -3 ) = 70 - 45
5 . ( x -3 ) = 25
( x -3 ) = 25 : 5
( x -3 ) = 5
x = 5 -3
x = 2
70-5.(x-3)=45
5.(x-3)=70-45
5.(x-3)=25
x-3=25:5
x-3=5
x=3+5
x=8
10+2.x=4^5:4^3
10+2.x=4^5-3
10+2.x=4^2
10+2.x=16
2.x=16-10
2.x=6
x=6:2
x=3
\(4^3:2^2\)
\(=\left(2^2\right)^3:2^2\)
\(=2^6:2^2\)
\(=2^{6-2}=2^4\)
\(5^7:5^5=5^{7-5}=5^2\)
1) 3.52 - 16 : 22
= 3 . 25 - 24 : 22
= 75 - 22
= 75 - 4
= 71
2) 23 .17 -23 . 14
= 23 . ( 17 - 14 )
= 8 . 3
= 24
3) 17.85 + 15.17 - 120
= 17 . ( 85 + 17 ) - 120
= 75 . 102 - 120
= 7650 - 120
= 7530
4) 20 - [30-(5 - 1)2]
= 20 - ( 30 - 42 )
= 20 - ( 30 - 16 )
= 20 - 14
= 6
5) 36 . 32 + 23 .22
= 38 + 25
= 6561 + 32
= 6593
6) 17 .85 + 15.17 - 120 + 20120
= 17 . ( 85 + 15 ) - 120 + 1
= 17 . 100 - 120 + 1
= 1700 - 120 + 1
= 1580 + 1
= 1581
7) 37. 24 + 37. 76 + 63 . 79 + 21. 63
= 37 . ( 24 + 76 ) + 63 . ( 79 + 21 )
= 37 . 100 + 63 . 100
= 100 . ( 37 + 63 )
= 100 . 100
= 10000
1) \(3.5^2-16.2^2=3.25-16.4=75-64=11\)
2) \(2^3.17-2^3.14=2^3.\left(17-14\right)=8.3=24\)
3) \(17.85+15.17-120=17.\left(85+15\right)-120\)
\(=17.100-120=1700-120=1580\)
4)\(20-\left[30-\left(5-1\right)^2\right]=20-\left[30-4^2\right]\)
\(=20-\left[30-16\right]=20-14=6\)
5) \(3^6.3^2+2^3.2^2=3^8+2^5=6561+32=6593\)
6) \(17.85+15.17-120+2012^0=17.\left(85+15\right)-120+1\)
\(=17.100-119=1700-119=1581\)
7) \(37.24+37.76+63.79+21.63\) \(=37.\left(24+76\right)+63.\left(79+21\right)\)
\(=37.100+63.100=100.\left(37+63\right)=100.100=10000\)
A = 1+4+\(4^2\)+\(4^3\)+...+\(4^{2018}\)
4.A = 4+ \(4^2\)+\(4^3\)+\(4^4\)+...+\(4^{2019}\)
_
A = 1+4+\(4^2\)+\(4^3\)+...+\(4^{2018}\)
3A = \(4^{2019}\)-1
\(A=1+4+4^2+...+4^{2018}\)
\(\Rightarrow4A=4+4^2+4^3+...+4^{2019}\)
\(\Rightarrow4A-A=\left(4+4^2+4^3+...+4^{2019}\right)-\left(1+4+4^2+...+4^{2018}\right)\)
\(\Rightarrow3A=4^{2019}-1\)
\(\Rightarrow A=\frac{4^{2019}-1}{3}\)
Vậy \(A=\frac{4^{2019}-1}{3}\)
_Chúc bạn học tốt_
\(a,79-\left(79-2021\right)=79-79+2021=2021\\ b,4^5:4^3-8=4^2-8=16-8=8\\ c,17.\left(-85\right)+17.85=\left(-17\right).85+17.85=85\left(17-17\right)=85.0=0\)
a) 79 - (79 - 2021) = 79 - 79 + 2021 = 2021
b) 45 : 43 - 8 = 42 - 8 = 16 - 8 = 8
c) 17 . (- 85) + 17 . 85 = 17 . (- 85 + 85) = 17 . 0 =0