tìm giá trị của n trong biểu thức sau:
24(5^2+1)(5^4+1)(5^8+1)(5^16+1)=5^n-1
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24.(52+1)(54+1).........(516+1)
=(52-1)(52+1)(54+1)........(516+1)
=(54-1)(54+1).........(516+1)
=(58-1)(58+1)(516+1)
=(516-1)(516+1)
=532-1
Q = 532 - 24(52 + 1)(54 + 1)(58 + 1)(516 + 1)
Q = 532 - (52 - 1)(52 + 1)(54 + 1)(58 + 1)(516 + 1)
Q = 532 - (54 - 1)(54 + 1)(58 + 1)(516 + 1)
Q = 532 - (58 - 1)(58 + 1)(516 + 1)
Q = 532 - (516 - 1)(516 + 1)
Q = 532 - (532 - 1)
Q = 532 - 532 + 1
Q = 1
\(Q=5^{32}-24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(=5^{32}-\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(=5^{32}-\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(=5^{32}-\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(=5^{32}-\left(5^{16}-1\right)\left(5^{16}+1\right)=5^{32}-\left(5^{32}-1\right)=1\)
\(Q=5^{32}-24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(=5^{32}-\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(=5^{32}-\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(=5^{32}-\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(=5^{32}-\left(5^{16}-1\right)\left(5^{16}+1\right)\)
\(=5^{32}-5^{32}+1\)
= 1
Lời giải:
a.
$\frac{5}{15}-\frac{1}{6}\times \frac{2}{5}=\frac{5}{15}-\frac{1}{15}=\frac{4}{15}$
b.
$\frac{8}{24}+\frac{3}{4}:\frac{1}{8}=\frac{1}{3}+6=\frac{19}{3}$
c.
$\frac{1}{7}: \frac{2}{8}-\frac{1}{7}=\frac{1}{7}\times 4-\frac{1}{7}$
$=\frac{1}{7}\times (4-1)=\frac{1}{7}\times 3=\frac{3}{7}$
3:
3/5:x=3
=>x=3/5:3=1/5
4:
a:
=1/5+4/5+4/11+7/11=1+1=2
b: =5/6+5/9-1/4
=30/36+20/36-9/36
=41/36
5: Tổng hai số là 100
Số bé là 100*2/5=40
Số lớn là 100-40=60
\(\Leftrightarrow n=32\)