-5/16.7/17+(-11/16).5/17-5/16
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d: \(\dfrac{5}{16}-\dfrac{5}{24}=\dfrac{5\cdot3}{48}-\dfrac{5\cdot2}{48}=\dfrac{5}{48}\)
e: \(-\dfrac{24}{17}-\left(-\dfrac{7}{17}-\dfrac{1}{16}\right)\)
\(=-\dfrac{24}{17}+\dfrac{7}{17}+\dfrac{1}{16}=-1+\dfrac{1}{16}\)
\(=-\dfrac{15}{16}\)
f: \(\dfrac{-11}{6}+\dfrac{2}{5}+\dfrac{-1}{6}\)
\(=\left(-\dfrac{11}{6}-\dfrac{1}{6}\right)+\dfrac{2}{5}\)
\(=-2+\dfrac{2}{5}=\dfrac{-8}{5}\)
3/14 × 5/17 + 11/14 × 5/17 + 12/17 × 5/16 + 12/17 × 11/16
= 5/17 × ( 3/14 + 11/14) + 12/17 × ( 5/16 + 11/16)
= 5/17 × 1 + 12/17 × 1
= 5/17 + 12/17
= 1
3/14 × 5/17 + 11/14 × 5/17 + 12/17 × 5/16 + 12/17 × 11/16
= 5/17 × ( 3/14 + 11/14) + 12/17 × ( 5/16 + 11/16)
= 5/17 × 1 + 12/17 × 1
= 5/17 + 12/17
= 1
\(\left(16.17-5\right):\left(16.16+11\right)\)
\(\frac{16.17-5}{16.16+11}\)
\(\frac{17-5}{16+11}\)
\(\frac{12}{27}\)
\(16.17-\dfrac{5}{16}\times16+11\)
\(=272-5+11\)
\(=278\)
\(-\dfrac{3}{17}+\left(\dfrac{2}{3}+\dfrac{3}{17}\right)=\dfrac{-3}{17}+\dfrac{3}{17}+\dfrac{2}{3}=\dfrac{2}{3}\)
\(\dfrac{-5}{21}+\dfrac{-16}{21}+1=-1+1=0\)
\(\dfrac{-4}{11}\cdot\dfrac{5}{15}\cdot\dfrac{11}{-4}=\dfrac{5}{15}=\dfrac{1}{3}\)
(16.17-5) : (16.20+11) = (272-5) : (320+11)
= 267:331
=0,8066465257
\(\frac{16×17-5}{16×16+11}\)
\(=\frac{17-5}{16+11}\)
\(=\frac{12}{27}\)
`a)4/5+5 1/2 xx (4,5-2)+7/10`
`=4/5+11/2*2,5+7/10`
`=0,8+2,2+0,7`
`=3+0,7=3,7`
`b)125%xx 17/4:(1 5/16-0,5)+2008`
`=1,25xx4,25:13/16+2008`
`=85/13+2008`
`=2014 7/13`
`c)5/11+(16/11+1)`
`=5/11+1+5/11+1`
`=2+10/11=32/11`
`d)3/17+11/4+5/8+14/17+3/8`
`=3/17+14/17+5/8+3/8+11/4`
`=1+1+11/4`
`=19/4`
a)
\(\dfrac{4}{5}+5\dfrac{1}{2}x\left(4,5-2\right)=\dfrac{7}{10}\)
<=> \(\dfrac{11}{2}x\times2,5=\dfrac{7}{10}-\dfrac{4}{5}=\dfrac{-1}{10}\)
<=> \(\dfrac{55}{4}x=\dfrac{-1}{10}< =>x=\dfrac{-2}{275}\)
b) \(125\%\times\dfrac{17}{4}:\left(1\dfrac{5}{16}-0,5\right)+2008\)
= \(\dfrac{85}{16}:\left(\dfrac{21}{16}-\dfrac{1}{2}\right)+2008=\dfrac{85}{16}:\dfrac{13}{16}+2008=\dfrac{26189}{13}\)
c) \(\dfrac{5}{11}+\left(\dfrac{16}{11}+1\right)\)
= \(\dfrac{21}{11}+1=\dfrac{32}{11}\)
d) \(\left(\dfrac{3}{17}+\dfrac{14}{17}\right)+\left(\dfrac{5}{8}+\dfrac{3}{8}\right)+\dfrac{11}{4}\)
= 1 + 1 + \(\dfrac{11}{4}\) = \(\dfrac{19}{4}\)
a
\(-\frac{16}{17}< -\frac{14}{17}< -\frac{12}{17}< -\frac{11}{17}< -\frac{9}{17}< -\frac{3}{17}< -\frac{1}{17}\)
b
\(-\frac{5}{2}< -\frac{5}{3}< -\frac{5}{4}< -\frac{5}{7}< -\frac{5}{8}< -\frac{5}{9}< -\frac{5}{11}\)
P/S:Lẽ ra ko lm bài này nhưng thấy chứ đang vội thì lm nốt:((
a) Vì -16 < -14 < -12 < -11 < -9 < -3 < -1
=> \(\frac{-16}{17}\), \(\frac{-14}{17}\), \(\frac{-12}{17}\), \(\frac{-11}{17}\), \(\frac{-9}{17}\), \(\frac{-3}{17}\), \(\frac{-1}{17}\)
b) Vì 2 < 3 < 4 < 7 < 8 < 9 < 11
mà theo lí thuyết ta có : phân số nào có mẫu lớn hơn thì phân số đó bé hơn và ngược lại
=> \(\frac{-5}{11}\), \(\frac{-5}{9}\), \(\frac{-5}{8}\), \(\frac{-5}{7}\), \(\frac{-5}{4}\), \(\frac{-5}{3}\), \(\frac{-5}{2}\)
~ Học tốt ~