x : 54 =27 ( dư 25)
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,123\times54+27\times123-12\times123+123\times31\)
\(=123\times\left(54+27-12+31\right)\)
\(=123\times100\)
\(=12300\)
\(b,\dfrac{121}{27}\times\dfrac{54}{11}< n< \dfrac{100}{21}:\dfrac{25}{126}\)
\(22< n< \dfrac{100}{21}\times\dfrac{126}{25}\)
\(22< n< 24\)
Vì \(23>22\) và \(23< 24\) nên \(n=23\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a123x54+27x123-12x123+123x31
=123:54+27:123-12:123+123:31
=6642+27:123-12:123+123:31
=6642+3321-12:123+123:31
=6642+3321-1476+123:31
=6642+3321-1476+3813
=12300
b,121/27x54/11<n>100/21:25/126
=22<n>24
n=23
![](https://rs.olm.vn/images/avt/0.png?1311)
3, 54 x 73 + 0,23 x 25 + 3,54 x 27 + 0,17 x 25
= 3,54 x 73 + 3,54 x 27 + 0,23 x 25 + 0,17 x 25
= 3,54 x(73+27) + 25 x (0,23+0,17)
= 3,54 x 100 + 25 x 0,4
= 3,54 x 100 + 10
= 35,4 x 10 + 10
= 10 x (35,4+1)
= 10 x 36,4
= 364
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.\frac{121}{27}\times\frac{54}{11}< n< \frac{100}{21}\div\frac{25}{126}\)
\(22< n< 24\)
\(\Rightarrow n=23.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 20x4+20x3+20x3
= 20 x ( 4+3 + 3)
= 20 x10
= 200
b) (6x9-54)x(25 +26+27+.........41+42)
= 0 x (25 +26+27+.........41+42)
= 0
20x4+20x3+20x3
= 20 x ( 4+3 + 3)
= 20 x10
= 200
b) (6x9-54)x(25 +26+27+.........41+42)
= 0 x (25 +26+27+.........41+42)
= 0
![](https://rs.olm.vn/images/avt/0.png?1311)
1) 42/35 - [ 33/14 . 21/22 - ( 54/25 : 27/25 - 7/10 )]
= 42/35 - ( 9/4-13/10)
=42/35-19/20
=1/4
2) a) 5/21 . x/34 = 35/102
x/34=35/102 : 5/21
x/34=49/34
=> x=34
Vậy x=34
b) 15/x . 21/13 = 45/91
15/x=45/91 : 21/13
15/x=15/49
=> x=49
Vậy x=49
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
x : 54 =27 ( dư 25)
x = 27 x 54 + 25
x =1483
HT
x = 27 * 54
x = 1458