35x6+11-32+100x32-3=?
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\(50^2-18^2+32^2+100\cdot32\)
\(=\left(32^2-18^2\right)+\left(50^2+100\cdot32\right)\)
\(=\left(32+18\right)\left(32-18\right)+50\cdot\left(50+2\cdot32\right)\)
\(=50\cdot14+50\cdot114\)
\(=50\cdot128\)
\(=6400\)
35 x 6 - 70 x 3 + 35
= 35 x 6 - 35 x 2 x 3 + 35
= 35 x 6 - 35 x 6 + 35
= 35 x ( 6 - 6 ) + 35
= 35 x 0 + 35
= 0 + 35
= 35
35 x 6 - 70 x 3 + 35
= 35 x 6 - 35 x 2 x 3 + 35 x 1
= 35 x 6 - 35 x 6 + 35 x 1
= 35 x ( 6 - 6 + 1 )
= 35 x 1
= 35
Cần gấp thì bạn cũng nên viết đầy đủ đề bài nhé.
** Bài toán rút gọn**
Lời giải:
\(\sqrt{17-12\sqrt{2}}=\sqrt{17-2\sqrt{72}}=\sqrt{9-2\sqrt{8.9}+8}=\sqrt{(\sqrt{9}-\sqrt{8})^2}\)
\(=\sqrt{9}-\sqrt{8}=3-2\sqrt{2}\)
\(\sqrt{24-8\sqrt{8}}=\sqrt{24-2\sqrt{128}}=\sqrt{16-2\sqrt{16.8}+8}=\sqrt{(\sqrt{16}-\sqrt{8})^2}\)
\(=\sqrt{16}-\sqrt{8}=4-2\sqrt{2}\)
\(\Rightarrow \sqrt{17-12\sqrt{2}}-\sqrt{24-8\sqrt{8}}=(3-2\sqrt{2})-(4-2\sqrt{2})=-1\)
--------------------
\(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}=\sqrt{17-12\sqrt{2}}+\sqrt{17+12\sqrt{2}}\)
\(=\sqrt{8-2\sqrt{8.9}+9}+\sqrt{8+2\sqrt{8.9}+9}\)
\(=\sqrt{(\sqrt{8}-\sqrt{9})^2}+\sqrt{(\sqrt{8}+\sqrt{9})^2}\)
\(=|\sqrt{8}-\sqrt{9}|+|\sqrt{8}+\sqrt{9}|=3-2\sqrt{2}+3+2\sqrt{2}=6\)
----------------------
\(\sqrt{11+6\sqrt{2}}-\sqrt{11-6\sqrt{2}}=\sqrt{9+2\sqrt{9.2}+2}-\sqrt{9-2\sqrt{9.2}+2}\)
\(=\sqrt{(\sqrt{9}+\sqrt{2})^2}-\sqrt{(\sqrt{9}-\sqrt{2})^2}\)
\(=|\sqrt{9}+\sqrt{2}|-|\sqrt{9}-\sqrt{2}|=3+\sqrt{2}-(3-\sqrt{2})=2\sqrt{2}\)
\(\sqrt{17-12\sqrt{2}}-\sqrt{24-8\sqrt{8}}=\sqrt{\left(3-2\sqrt{2}\right)^2}-\sqrt{\left(4-2\sqrt{2}\right)^2}\)
\(=\left|3-2\sqrt{2}\right|-\left|4-2\sqrt{2}\right|=3-2\sqrt{2}-4+2\sqrt{2}\)
\(=-1\)
\(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}=\sqrt{\left(3-2\sqrt{2}\right)^2}+\sqrt{\left(3+2\sqrt{2}\right)^2}\)
\(=\left|3-2\sqrt{2}\right|+\left|3+2\sqrt{2}\right|=3-2\sqrt{2}+3+2\sqrt{2}\)
\(=6\)
\(\sqrt{11+6\sqrt{2}}-\sqrt{11-6\sqrt{2}}=\sqrt{\left(3+\sqrt{2}\right)^2}-\sqrt{\left(3-\sqrt{2}\right)^2}\)
\(=\left|3+\sqrt{2}\right|-\left|3-\sqrt{2}\right|=3+\sqrt{2}-3+\sqrt{2}\)
\(=2\sqrt{2}\)
Bài 1:
\(=\dfrac{-3-39}{42}+\dfrac{-6-11}{17}-\dfrac{1}{6}=-\dfrac{119}{48}\)
Bài 2:
=>x:5=-13/20
hay x=-65/20=-13/4
\(3^2\times\left[\left(5^2-3\right)\div11\right]-2^4+2\times10^3\)
\(=9\times\left[\left(25-3\right)\div11\right]-16+2\times1000\)
\(=9\times\left(22\div11\right)-16+2000\)
\(=9\times2-16+2000\)
\(=18-16+2000\)
\(=2+2000\)
\(2002\)
`a) 3-5+(-x+3)=6`
`=>5+(-x+3)=3-6`
`=>5+(-x+3)=-3`
`=>-x+3=-3-5`
`=>-x+3=-8`
`=>-x=-8-3`
`=>-x=-11`
`=>x=11`
__
`b)(-4-x)+(4-15)=-15`
`=>(-4-x)+-11=-15`
`=>-4-x=-15-(-11)`
`=>-4-x=-15+11`
`=>-4-x=-4`
`=>x=-4-(-4)`
`=>x=-4+4`
`=>x=0`
`c)(11+x)-(-11-9)=32`
`=>(11+x)-(-20)=32`
`=>(11+x)+20=32`
`=>11+x=32-20`
`=>11+x=12`
`=>x=12-11`
`=>x=1`
`a)3-5+(-x+3)=6`
`5+(-x+3)=3-6`
`5+(-x+3)=-3`
`-x+3=-3-5`
`-x+3=-8`
`-x=-8-3`
`-x=-11`
`x=11`
`b,(-4-x)+(4-15)=-15`
`(-4-x)+(-11)=-15`
`-4-x=-15-(-11)`
`-4-x=-15+11`
`-4-x=-4`
`x=-4-(-4)`
`x=-4+4`
`x=0`
`c)(11+x)-(-11-9)=32`
`(11+x)-(-20)=32`
`(11+x)+20=32`
`11+x=32-20`
`11+x=12`
`x=12-11`
`x=1`
TL
35x6+11-32+100x32-3=9.245
~HT~
HOk tốt!
@@
35*6+11-32+100*32-3
=210+11+3200-3
=221+3200-3
=3421-3
=3418