23 + 23 + 41 + 68 + 2 =.....
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Bài làm
32 . 23 + 32 . 41 + 64 . 68
= 32 . 23 + 32 . 41 + 32 . 2 . 68
= 32 . 23 + 32 . 41 + 32 . 136
= 32 . ( 23 + 41 + 136 )
= 32 . 200
= 6400
# Học tốt #
32 . 23 + 32 . 41 + 64 . 68
= 32 .(23 + 41) + 64 . 68
= 32 . 64 + 64 . 68
= 64 . ( 32 + 68 )
= 64 . 100
= 6400
k mình nha.Hok tốt
\(\frac{27}{23}+\frac{-4}{23}+\frac{1}{2}+\frac{-4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)
\(\Rightarrow\frac{27}{23}-\frac{4}{23}+\frac{1}{2}-\frac{4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)
\(\Rightarrow1+0< x< \frac{7}{3}+\frac{3}{3}\)
\(\Rightarrow1< x< \frac{10}{3}\)
\(\Rightarrow1< x< 3,333333333\)
\(\Rightarrow x\in\left\{2;3\right\}\)
Vậy : ....
ta co : \(\frac{27}{23}+\frac{-4}{23}+\frac{1}{2}+\frac{-4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)
=> \(1< x< \frac{10}{3}\)
vi x la so nguyen => \(1< x\le3\)
con lai ban tu lam
Đáp án:
a, 38+41+117+159+6238+41+117+159+62
=(38+62)+(41+159)+117=(38+62)+(41+159)+117
=100 +200 +117=100 +200 +117
=417=417
b, 73+86+968+914+303273+86+968+914+3032
=73+(86+914)+(968+3032)=73+(86+914)+(968+3032)
=73+1000 +4000=73+1000 +4000
=5073=5073
c, 341.67+341.16+659.83341.67+341.16+659.83
=341.(67+16)+659.83=341.(67+16)+659.83
=341.83+659.83=341.83+659.83
=83.(341+659)=83.(341+659)
=83.1000=83000=83.1000=83000
d, 42.53+47.156−47.11442.53+47.156-47.114
=42.53+47.(156−114)=42.53+47.(156-114)
=42.53 +47.42=42.53 +47.42
=42.(53+47)=42.100=42.(53+47)=42.100
=4200=4200
e, 563.23+23.26+23563.23+23.26+23
=23.(563+26+1)=23.(563+26+1)
=23.600=23.600
=13800=13800
f, 132+157+43+68132+157+43+68
=(132+68)+(157+43)=(132+68)+(157+43)
=200 +200=400=200 +200=400
g, 49.68+100.34+6849.68+100.34+68
=49.68+50.68+68=49.68+50.68+68
=68.(49+50+1)=68.(49+50+1)
=68.100=6800=68.100=6800
h, 491.(267+53)+491.(151+67)491.(267+53)+491.(151+67)
=491.(267+53+151+67)=491.(267+53+151+67)
=491.538=491.538
=264158=264158
Vote mk nha.
\(B=\frac{23^{41}+1}{23^{42}+1}\)
Vì B < 1
\(\Rightarrow B=\frac{23^{41}+1}{23^{42}+1}< \frac{23^{41}+1+22}{23^{42}+1+22}=\frac{23^{41}+23}{23^{42}+23}=\frac{23(23^{40}+1)}{23\left(23^{41}+1\right)}=\frac{23^{40}+1}{23^{41}+1}=A\)
P/s: Hoq chắc
ta có
\(B=\frac{23^{41}+1}{23^{42}+1}< \frac{23^{41}+1+22}{23^{42}+1+22}=\frac{23^{41}+23}{23^{42}+23}=\frac{23\left(23^{40}+1\right)}{23\left(23^{41}+1\right)}=\frac{23^{40}+1}{23^{41}+1}=A\)
\(\Rightarrow B< A\)
A=((2-2/19+2/23-1/1010)/(3-3/19+3/23-3/2020))x((4-4/29+4/41-1/505)/(5-5/29+5/41-1/404))
giúp mình với
a) 65 000 ; 66 000 ; 67 000 ; 68 000 ; 69 000 ; 70 000 ; 71 000.
b) 85 700 ; 85 800 ; 85 900 ; 86 000 ; 86 100 ; 86 200 ; 86 300.
c) 23 450 ; 23 460 ; 23 470 ; 23 480 ; 23 490 ; 23 500 ; 23 510.
d) 23 458 ; 23 459 ; 23 460 ; 23 461 ; 23 462 ; 23 463 ; 23 464.
\(23+23+41+68+2=157\)
23 + 23 + 41 + 68 + 2 = 157