Bài 2(2,5 điểm): Tìm số tự nhiên x, biết
a)2x+34=56
b)87–(x – 654):3= 21
c)765:7X = 743.721
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2:
a: x+201=351
=>x=351-201
=>x=150
b: \(8\cdot5^2-27:25\)
\(=8\cdot25-\dfrac{27}{25}\)
\(=200-1,08=198,92\)
d: \(2023-23:\left[9+2\left(2^3-0,21\right)\right]\)
\(=2023-23:\left[9+16-0,42\right]\)
\(=2023-\dfrac{23}{25-0,42}\)
\(=2023-\dfrac{1150}{1229}=\dfrac{2485117}{1229}\)
b: 2(x-21)=84
=>x-21=84/2=42
=>x=42+21=63
c: 135-4(81-x)=55
=>4(81-x)=135-55=80
=>81-x=20
=>x=61
a) \(\Leftrightarrow2x+5=3^6\\ \Leftrightarrow2x+5=729\\ \Leftrightarrow x=362\)
b) \(\Leftrightarrow x+55=60\\ \Leftrightarrow x=5\)
c) \(x=\left\{12;24;36;48\right\}\)
a: =>12x-64=32
=>12x=96
=>x=8
b: =>x-1=5
=>x=6
c: =>2^x*3=96
=>2^x=32
=>x=5
Bài 2:a, x+17=109
x =109-17
x =92
b,x+34=56+42+43
x+34=141
x =141-34
x =107
c,2x+45=x+94
2*x =x+94-45
x+x =x+49
suy ra x=49
d,x+109=1+2+3+........+99
x+109=495
x =495-109
x =386
Bài 1 mik ko có làm được.
a, 91 - 5 . ( 5 + x ) = 61
5 . (5+x)=91-61
5 . (5+x)=30
5+x=30:5
5+x=6
x=6-5
x=1
Bài 1. Tìm số tự nhiên x biết:
a, 91 - 5 . ( 5 + x ) = 61
5(5 + x) = 91 - 61
5(5 + x) = 30
5 + x = 30 : 5
5 + x = 6
x = 6-5
x= 1
b, ( x+ 34 ) - 50 = 56 : 2
( x + 34 ) - 50 = 28
x + 34 = 28 + 50
x + 34 = 68
x= 78 - 34
x = 44
Tk mk nha
\(a,-\dfrac{13}{20}+x=\dfrac{-11}{15}\\ \Rightarrow x=\dfrac{-11}{15}+\dfrac{13}{20}\\ \Rightarrow x=-\dfrac{1}{12}\\ b,\left(x-3,5\right):3\dfrac{1}{2}-2,5=-1\dfrac{3}{4}\\ \Rightarrow\left(x-\dfrac{7}{2}\right):\dfrac{7}{2}-\dfrac{5}{2}=\dfrac{-7}{4}\\ \Rightarrow\left(x-\dfrac{7}{2}\right):\dfrac{7}{2}=\dfrac{3}{4}\\ \Rightarrow x-\dfrac{7}{2}=\dfrac{21}{8}\\ \Rightarrow x=\dfrac{49}{8}\)
Lời giải:
a.
$0< x< \frac{1}{4}+\frac{4}{5}$
$\Rightarrow 0< x< \frac{21}{20}$ hay $0< x< 1,05$
$\Rightarrow x=1$
b.
$\frac{4}{7}+\frac{3}{7}< x< \frac{5}{3}+\frac{2}{3}$
$\Rightarrow 1< x< \frac{7}{3}$
$\Rightarrow x=2$
\(a,2x+34=56\\ \Rightarrow2x=56-34\\ \Rightarrow x=22:2\\ \Rightarrow x=11\\ b,87-\left(x-654\right):3=21\\ \Rightarrow\left(x-654\right):3=87-21\\ \Rightarrow x-654=66:3\\ \Rightarrow x=22+654\\ \Rightarrow x=676\\ c,7^{65}:7^x=7^{43}.7^{21}\\ \Rightarrow7^{65-x}=7^{43+21}\\ \Rightarrow65-x=64\\ \Rightarrow x=65-64\\ \Rightarrow x=1\)