x+(-45)=(-62)+17
(689-31)-(269-111)
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a) (871 - 28 ) + ( 229 - 72 )
= 871 - 28 + 229 - 72
= (871 + 229) - (28 + 72)
= 1100 + 100 = 1200
b) ( 689 - 31 ) - ( 269 - 111 )
= 689 - 31 - 269 + 111
= (689 + 111) - (31 + 269)
= 800 - 300= 500
c) 215 + ( - 38) - ( - 58) + 90 - 85
= 215 - 38 + 58 + 90 - 85
= (215 - 85) + (58 - 38) + 90
= 130 + 20 + 90 = 240
d) 31 - [ 26 - ( 209 + 35 ) ]
= 31 - 26 + 209 + 35
= (31 + 209) + (35 - 26)
= 240 + 9 = 249
e) ( 1267 - 196 ) - ( 267 + 304 )
= 1267 - 196 - 67 - 304
= (1267 - 67) - (196 + 304)
= 1200 - 500 = 700
f) ( 3965 - 2378 ) - ( 437 - 1378 ) - 528
= 3965 - 2378 - 437 + 1378 - 528
= 3965 - (2378 - 1378) - (437 + 528)
= 3965 - 1000 - 965 = 3000 - 1000 = 2000
Chúc em học tốt!!!
Bài 1:
a, (-8) . 25. (-2) . 125 . (-5)
= [(-8) . 125] .[ 25 . (-5)]
= (-1000) . (-125)
= 125 000
a, = 113 x (54+45+1) = 113 x 100 = 11300
b, = (36+62) x (117-17) = 98 x 100 = 9800
k mk nha
\(a.\)
\(\dfrac{27}{13}-\dfrac{106}{111}+-\dfrac{5}{111}=\dfrac{27}{13}-\dfrac{106}{111}-\dfrac{5}{111}=\dfrac{27}{13}-\left(\dfrac{106+6}{111}\right)=\dfrac{27}{13}-1=\dfrac{14}{13}\)
\(b.\)
\(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\dfrac{7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+1=\dfrac{23}{11}\)
\(c.\)
\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+-\dfrac{6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)-\left(\dfrac{25}{31}+\dfrac{6}{31}\right)=1-1=0\)
a) \(\dfrac{27}{13}-\dfrac{106}{111}+\dfrac{-5}{111}=\dfrac{27}{13}+\left(\dfrac{-106}{111}+\dfrac{-5}{111}\right)=\dfrac{27}{13}+-1=\dfrac{14}{13}\)
b) \(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\left(\dfrac{7}{19}+\dfrac{12}{19}\right)=\dfrac{12}{11}+1=\dfrac{23}{11}\)
c)\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+\dfrac{-6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)+\left(\dfrac{-25}{31}+\dfrac{-6}{31}\right)=1+-1=0\)
x+(-45)=(-62)+17
x+(-45)=-45
x =-45+45
x =0
(689-31)-(269-111)
=689-31-269+111
=(689+111)-(31+269)
= 800 - 300
= 500
1) x + ( -45 ) = -45
x = -45 - ( -45)
x= 0