tính tổng 3^0+3^1+...+3^2015
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S = (-3)0 + (-3)1 + (-3)2 + ... + (-3)2015
=> 3S = (-3)1 + (-3)2 + (-3)3 + ... + (-3)2016
=> 3S + S = [(-3)1 + (-3)2 + ... + (-3)2016] + [(-3)0 + (-3)1 + ... + (-3)2015]
=> 4S = (-3)2016 + (-3)0
=> S = \(\frac{\left(-3\right)^{2016}+\left(-3\right)^0}{4}\)
S=1-3+32-33+...+32014-32015
=>3S=3-32+...+32015-32016
=>3S+S=4S=(3-32+...+32015-32016)+(1-3+...+32014-32015)
=>4S=-32016+1
=>S=\(-\frac{3^{2016}-1}{4}\)
\(S=\left(-3\right)^0+\left(-3\right)^1+\left(-3\right)^2+\left(-3\right)^3+........+\left(-3\right)^{2015}\)
\(\Rightarrow-3S=\left(-3\right)^1+\left(-3\right)^2+\left(-3\right)^3+\left(-3\right)^4+......+\left(-3\right)^{2016}\)
\(\Rightarrow-4S=\left[\left(-3\right)^1+\left(-3\right)^2+...+\left(-3\right)^{2016}\right]-\left[\left(-3\right)^0+\left(-3\right)^1+...+\left(-3\right)^{2015}\right]\)
\(\Rightarrow-4S=\left(-3\right)^{2016}-\left(-3\right)^0\Rightarrow-4S=3^{2016}-1\Rightarrow S=\frac{3^{2016}-1}{-4}\)
Tính tổng
S=\(\left(-3\right)^0+\left(-3\right)^1+\left(-3\right)^2+........+\left(-3\right)^{2015}\)
Trả lời:
\(S=\) \(\left(-3\right)^0+\left(-3\right)^1+\left(-3\right)^2+...+\)\(\left(-3\right)^{2015}\)
\(-3S=\)\(\left(-3\right)^1+\left(-3\right)^2+...+\)\(\left(-3\right)^{2016}\)
\(-3S-S=\)\([\left(-3\right)^1+\left(-3\right)^2+...+\)\(\left(-3\right)^{2016}\)\(]\)\(-\)\([\)\(\left(-3\right)^0+\left(-3\right)^1+\left(-3\right)^2+...+\)\(\left(-3\right)^{2015}\)\(]\)
\(\left(-3-1\right)S=\)\(\left(-3\right)^1+\left(-3\right)^2+...+\)\(\left(-3\right)^{2016}\)\(-\)\(\left(-3\right)^0-\left(-3\right)^1-\left(-3\right)^2-...-\)\(\left(-3\right)^{2015}\)
\(-4S=\)\(\left[\left(-3\right)^1-\left(-3\right)^1\right]\)\(+\)\(\left[\left(-3\right)^2-\left(-3\right)^2\right]\)\(+\)\(...\)\(+\)\(\left[\left(-3\right)^{2015}-\left(-3\right)^{2015}\right]\)\(+\)\(\left[\left(-3\right)^{2016}-\left(-3\right)^0\right]\)
\(-4S=\)\(0+0+...+0+\left(-3\right)^{2016}-1\)
\(-4S=\)\(3^{2016}-1\)
\(S=\frac{-3^{2016}+1}{4}\)
Vậy \(S=\frac{-3^{2016}+1}{4}\)
P/s: Không chắc có đúng ko.
Hok tốt!
Vuong Dong Yet
( - 3) . S = (- 3) + ( - 3)2 +...+ ( - 3)2016
( - 3) . S - S = ( - 3)2016 - 1
( - 4 ) S = ( - 3)2016 - 1
S = [ ( - 3 )2016 - 1 ] : ( - 4)
Đăt A=30+31+.............+32015
3A=31+32+...........+32016
3A-A=(31+32+..........+32016)-(30+31+..............+32015)
2A=32016-30
A=\(\frac{3^{2016}-1}{2}\)
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