Tìm y, biết:
y x 6 - 12 = y x 3
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\(\dfrac{x}{6}=\dfrac{y}{3}\)và x-y=12
Áp dụng tính chất dãy tỉ số bằng nhau ta có
\(\dfrac{x}{6}=\dfrac{y}{3}=\dfrac{x-y}{6-3}=\dfrac{12}{3}=4\)
\(Vậy\dfrac{x}{6}=4\Rightarrow4.6=24\)
\(\dfrac{y}{3}=4\Rightarrow4.3=12\)
vậy x=24;y=12
Bài 9:
Ta có: \(\dfrac{12}{-6}=\dfrac{x}{5}=\dfrac{-y}{3}=\dfrac{z}{-17}=\dfrac{-t}{-9}\)
\(\Leftrightarrow\dfrac{x}{5}=\dfrac{-y}{3}=\dfrac{-z}{17}=\dfrac{t}{9}=-2\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{x}{5}=-2\\\dfrac{-y}{3}=-2\\\dfrac{-z}{17}=-2\\\dfrac{t}{9}=-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-10\\-y=-6\\-z=-34\\t=-18\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-10\\y=6\\z=34\\t=-18\end{matrix}\right.\)
Vậy: (x,y,z,t)=(-10;6;34;-18)
Bài 11:
Ta có: \(\dfrac{-7}{6}=\dfrac{x}{18}=\dfrac{-98}{y}=\dfrac{-14}{z}=\dfrac{t}{102}=\dfrac{u}{-78}\)
\(\Leftrightarrow\dfrac{x}{18}=\dfrac{-98}{y}=\dfrac{-14}{z}=\dfrac{t}{102}=\dfrac{u}{-78}=\dfrac{-7}{6}\)
Ta có: \(\dfrac{x}{18}=\dfrac{-7}{6}\)
\(\Leftrightarrow x=\dfrac{18\cdot\left(-7\right)}{6}=-21\)
Ta có: \(\dfrac{-98}{y}=\dfrac{-7}{6}\)
\(\Leftrightarrow y=\dfrac{-98\cdot6}{-7}=84\)
Ta có: \(\dfrac{-14}{z}=\dfrac{-7}{6}\)
\(\Leftrightarrow z=\dfrac{-14\cdot6}{-7}=12\)
Ta có: \(\dfrac{u}{-78}=\dfrac{-7}{6}\)
\(\Leftrightarrow u=\dfrac{-78\cdot\left(-7\right)}{6}=\dfrac{78\cdot7}{6}=91\)
Ta có: \(\dfrac{t}{102}=\dfrac{-7}{6}\)
\(\Leftrightarrow t=\dfrac{-7\cdot102}{6}=-7\cdot17=-119\)
Vậy: (x,y,z,t,u)=(-21;84;12;-119;91)
\(\frac{x}{3}=\frac{y}{5}=\frac{z}{6}=\frac{x+y-z}{3+5-6}=\frac{12}{2}=6\)
x =3.6=18
y=5.6=30
z=6.6 =36
x/3=y/5=z/6
áp dụng t/c dãy tỉ số = nhau ta có :
x/3=y/5=z/6=x+y-z/3+5-6=12/2=6
=>x=3.6=18
y=5.6=30
z=6.6=36
a) Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{7}=\dfrac{y}{6}=\dfrac{x-y}{7-6}=\dfrac{80}{1}=80\)
\(\Rightarrow\dfrac{x}{7}=80\Rightarrow x=80\cdot7=560\)
\(\Rightarrow\dfrac{y}{6}=80\Rightarrow y=80\cdot6=480\)
b) Áp dụng tính chất dãy tỉ số bằng nhau ta có::
\(\dfrac{x}{4}=\dfrac{y}{7}=\dfrac{x+y}{4+7}=\dfrac{12}{11}\)
\(\Rightarrow\dfrac{x}{4}=\dfrac{12}{11}\Rightarrow x=\dfrac{4\cdot12}{11}=\dfrac{48}{11}\)
\(\Rightarrow\dfrac{y}{7}=\dfrac{12}{11}\Rightarrow y=\dfrac{7\cdot12}{11}=\dfrac{84}{11}\)
Mình làm mẫu 2 câu thôi nhé
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\(\frac{12}{-6}=\frac{x}{5}\Rightarrow x=\frac{12.5}{-6}=\frac{2.3.2.5}{-1.2.3}=\frac{2.5}{-1}=\frac{10}{-1}=-10\)
\(\frac{-10}{5}=\frac{-y}{3}\Rightarrow-y=\frac{-10.3}{5}=\frac{-1.2.5.3}{5}=\frac{-1.2.3}{1}=\frac{-6}{1}=-6\Rightarrow y=6\)
\(\frac{-6}{3}=\frac{z}{-7}\Rightarrow z=\frac{-6.\left(-7\right)}{3}=\frac{-2.3.\left(-7\right)}{3}=\frac{-2.\left(-7\right)}{1}=14\)
Vậy x = 10 ; y = 6 ; z = 14
Ta có:\(\frac{12}{-6}=\frac{-60}{30}=\frac{-10}{5}=\frac{-6}{3}=\frac{-42}{21}=\frac{14}{-7}\)
=>x=-10
-y=-6
z=14
=>x=-10
y=6
z=14
a,+) 4/x=12/15
=>15*4=12*x
=>60=12*x
=>x=5;có 4/x=y/45
=>4/5=y/45
=>36/45=y/45
=>y=36
Vậy x=5:y=36
b,3/x=1/y=6/24
=>3/x=1/y=1/4
có: 1/y=1/4
=>y=4
có: 1/4=3/x
=>1x=3*4
=>x=12
Vây x=12
y=4
hok tot
a) \(\frac{4}{5}=\frac{12}{15}=\frac{36}{45}\)
Tự giải quyết nốt =))