a) 4(x-3)=28
b) 5x +12=37
c) 70-5(x+4)=45
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a: \(\Leftrightarrow2\sqrt{2x}-10\sqrt{2x}+21\sqrt{2x}=28\)
=>\(13\sqrt{2x}=28\)
=>căn 2x=28/13
=>2x=784/169
=>x=392/169
b: \(\Leftrightarrow2\sqrt{x-5}+\sqrt{x-5}-\sqrt{x-5}=4\)
=>2*căn x-5=4
=>căn x-5=2
=>x-5=4
=>x=9
c: =>\(\sqrt{x-2}\left(\sqrt{x+2}-1\right)=0\)
=>x-2=0 hoặc x+2=1
=>x=-1 hoặc x=2
\(a,12\left(x-1\right)=0\\ x-1=0\\ x=1\\ b,45+5\left(x-3\right)=70\\ 5\left(x-3\right)=25\\ x-3=5\\ x=8\\ c,3.x-18:2=12\\ 3.x-9=12\\ 3.x=21\\ x=7\)
+/ 70-5(x-3)=45
5(x-3)=70-45
5(x-3)=25
x-3=25:5
x-3=5
x =5+3
x =8
+/ x-38:16=12
x-2,375=12
x =12+2.375
x = 14,375
+/ 10+2x=45:43
10+2x=16
2x=16-10
2x=6
x=6:2
x=3
k và kết bạn với mình nha <3
a)13-2(x+1)=7
2.(x+1)=13-7
2.(x+1)=6
x+1=6/2
x+1=3
x=3-1
x=2
a, 13 - 2 ( x + 1 ) = 7
2 .( x + 1 ) = 13 - 7
2 .( x + 1 ) = 6
x + 1 = 6 : 2
x + 1 = 3
x = 3 - 1
x = 4
Bài 3:
Gọi số nhóm là x
Theo đề, ta có: \(x\in\left\{1;2;3;4;6;9;12;18;36\right\}\)
mà 2<x<6
nên \(x\in\left\{3;4\right\}\)
Vậy: Có 2 cách chia nhóm
a) 25 - x = 12 + 6 =18
x=25-18=7 Vậy x=7
b) 7 + 2 x ( x -3 ) = 11
2.(x-3)=11-7=4
x-3=4:2=2
x=3+2=5
c) 102 : ( 2.x + 13) : 4) = 6
(2.x+13):4=102:6=17
2.x+13=17.4=68
2.x=68-13=55
x=27,5 Vậy x=27,5
Bài 3:
Gọi số nhóm là x
Theo đề, ta có: x∈{1;2;3;4;6;9;12;18;36}x∈{1;2;3;4;6;9;12;18;36}
mà 2<x<6
nên x∈{3;4}x∈{3;4}
Vậy: Có 2 cách chia nhóm
còn bài 1 chắc bn làm đc nha tick mk nha
a) ? × 4 = 28
28 : 4 = 7
Vậy 7 × 4 = 28.
b) ? × 3 = 12
12 : 3 = 4
Vậy 4 × 3 = 12.
c) 6 × ? = 24
24 : 6 = 4
Vậy 6 × 4 = 24.
Bài 1:
a) Ta có: \(\dfrac{2}{5}\cdot x+\dfrac{1}{3}=\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{2}{5}\cdot x=\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{-2}{15}\)
\(\Leftrightarrow x=\dfrac{-2}{15}:\dfrac{2}{5}=\dfrac{-2}{15}\cdot\dfrac{5}{2}\)
hay \(x=-\dfrac{1}{3}\)
Vậy: \(x=-\dfrac{1}{3}\)
b) Ta có: \(\dfrac{1}{5}+\dfrac{5}{3}:x=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{5}{3}:x=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{3}{10}\)
\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{3}{10}=\dfrac{5}{3}\cdot\dfrac{10}{3}\)
hay \(x=\dfrac{50}{9}\)
Vậy: \(x=\dfrac{50}{9}\)
c) Ta có: \(\dfrac{4}{9}-\dfrac{5}{3}\cdot x=-2\)
\(\Leftrightarrow\dfrac{5}{3}x=\dfrac{4}{9}+2=\dfrac{22}{9}\)
\(\Leftrightarrow x=\dfrac{22}{9}:\dfrac{5}{3}=\dfrac{22}{9}\cdot\dfrac{3}{5}\)
hay \(x=\dfrac{22}{15}\)
Vậy: \(x=\dfrac{22}{15}\)
d) Ta có: \(\dfrac{5}{7}:x-3=\dfrac{-2}{7}\)
\(\Leftrightarrow\dfrac{5}{7}:x=\dfrac{-2}{7}+3=\dfrac{19}{21}\)
\(\Leftrightarrow x=\dfrac{5}{7}:\dfrac{19}{21}=\dfrac{5}{7}\cdot\dfrac{21}{19}\)
hay \(x=\dfrac{15}{19}\)
Vậy:\(x=\dfrac{15}{19}\)
a) Ta có: \(\sqrt{4-5x}=12\)
\(\Leftrightarrow4-5x=144\)
\(\Leftrightarrow5x=-140\)
hay x=-28
b) Ta có: \(\sqrt{10+\sqrt{3x}}=2+\sqrt{6}\)
\(\Leftrightarrow\sqrt{3x}+10=10+4\sqrt{6}\)
\(\Leftrightarrow\sqrt{3x}=4\sqrt{6}\)
\(\Leftrightarrow3x=96\)
hay x=32
c) Ta có: \(\sqrt{4x+20}-3\sqrt{x+5}+\dfrac{4}{3}\sqrt{9x+45}=6\)
\(\Leftrightarrow2\sqrt{x+5}-3\sqrt{x+5}+\dfrac{4}{3}\cdot3\sqrt{x+5}=6\)
\(\Leftrightarrow x+5=4\)
hay x=-1
\(71-\left(33+x\right)=26\)
<=> \(71-33-x=26\)
<=> \(38-x=26\)
<=> \(x=38-26=12\)
\(3636:\left(12x-91\right)=36\)
<=> \(12x-91=101\)
<=> \(12x=192\)
<=> \(x=16\)
\(\left(x-15\right)-218=0\)
<=> \(x-15=218\)
<=> \(x=233\)
\(45+\left(x-6\right).3=81\)
<=> \(\left(x-6\right).3=36\)
<=> \(x-6=12\)
<=> \(x=18\)
\(124x-4x-70x=150\)
<=> \(\left(124-4-70\right).x=150\)
<=> \(50x=150\)
<=> \(x=3\)
1) 71 - ( 33 + x ) = 26
<=> 33 + x = 71 - 26
<=> 33 + x = 45
<=> x = 12
2) 3636 : ( 12x - 91 ) = 36
<=> 12x - 91 = 101
<=> 12x = 192
<=> x = 16
3) ( x - 15 ) - 218 = 0
<=> x - 15 = 218
<=> x = 218 + 15
<=> x = 233
4) 45 + ( x - 6 ) .3 = 81
<=> 45 + ( x - 6 ) = 27
<=> x - 6 = -18
<=> x = -12
5) 124x - 4x - 70x = 150
<=> 5x = 150
<=> x = 150 : 50
<=> x = 3
a) 4(x-3) =28 b) 5x+12=37 c) 70-5(x+4)=45
(x-3) =28 : 4 5x= 37-12 70(x+4)=45-5
(X-3)= 7 5x= 25 70(x+4)= 40
x = 7+3 x=25: 5 x +4=70.40
x = 10 x= 5 x+ 4= 2800
x=2800-4
x= 2796
cám ơn bạn BẢO HÀ nha